Question

我正在尝试将2张照片保存到我的MySQL数据库中。我只能看到数据库中的2张照片中的一张（即它的名字），但我看到我存储照片的文件夹中的2张照片。（附上数据库外观的图片。）当我尝试显示2张照片时，我只看到我在数据库中看到的那张照片。这有什么问题？

上传照片的Html代码

<input type="file" id="_photo" name="_photo[]" multiple="multiple">
<input type="button" id="add_more" class="" value="Add More Files"/>

将照片保存在数据库和文件夹中的代码

    if (!empty($_FILES['_photo']['name'][$i])) {
        if ($_FILES['_photo']['type'][$i] == 'image/jpeg') {
            $upload_folder = "./profile_pix/";
            $pic_name = time() . ".jpg";
            $pic_path = $upload_folder . $pic_name;
            require_once "include/resize.php";
                if (move_uploaded_file($_FILES['_photo']['tmp_name'][$i], $pic_path)) {
                    $image = new Resize($pic_path);
                    $image->resizeImage(180, 180, 'crop');
                    $image->saveImage($pic_path);
                    //thumbnail
                    $image = new Resize($pic_path);
                    $image->resizeImage(50, 50, 'crop');
                    $image->saveImage($upload_folder . "thumb/" . $pic_name);
                }
        }
    }
    else {
    $pic_name="default_house.png";
    }
    $sql = "INSERT INTO offers
                (accommodation, school, date,  available, member_id, photo, )
                 VALUES
                (:accommodation, :school, :date, 'yes', :member_id, '$pic_name', )"; 

$query = $db->($sql, array(..........));

显示上传照片的代码

$sql = "SELECT * FROM myDatabase";
foreach ($db->query($sql) AS $result){
echo "
<img src='profile_pix/{$result['photos']}' width = '30' height ='30px' style=' margin-top:8px;'/>
";
}enter image description here

Answer 1

尝试以下操作，希望它能够正常运行。请记住，您的专栏是photo，而不是photos。

<?php
   $sql = "SELECT * FROM myDatabase";
   $sqlres = mysql_query($sql);
   foreach ($sqlres AS $result){
     echo "<img src='profile_pix/".$result['photo']." width = '30' height ='30px' style=' margin-top:8px;'/>";
   }
?>

显示多张照片时出错

1 个答案: