Question

我有一个每隔0.~2秒执行一次的功能（由于滞后）。但是，我想每隔5秒钟进行一次祝酒。我可以知道如何实现这一目标吗？

 public void navigation(Coordinate userPosition , Coordinate destination){
     if (Math.abs(userPosition.y - destination.y) > 500) {
     {Toast.makeText(this, "Walk for " + Math.abs(CheckPoint.y - UserPosition.y) + "mm", Toast.LENGTH_SHORT).show(); }
 }

以上是我当前代码的示例。吐司执行的频率取决于当前的延迟＆＃39;。我希望最少每5秒发送一次吐司。

Answer 1

你可以这样做：

    final Handler handler = new Handler();
    handler.postDelayed(new Runnable() {
        @Override
        public void run() {
            navigation(...);
            handler.postDelayed(this, 5000);
        }
    }, 5000);

Answer 2

试试这五秒钟，

 int count = 100; //Declare as inatance variable

    Timer timer = new Timer();
    timer.schedule(new TimerTask() {

        @Override
        public void run() {
            runOnUiThread(new Runnable() {

                @Override
                public void run() {
                    final Toast toast = Toast.makeText(
                            getApplicationContext(), --count + "",
                            Toast.LENGTH_SHORT);
                    toast.show();
                    Handler handler = new Handler();
                    handler.postDelayed(new Runnable() {

                        @Override
                        public void run() {
                            toast.cancel();
                        }
                    }, 5000);

                }
            });
        }
    }, 0, 5000);

Answer 3

创建一个Thread并循环该线程

    Thread myThread = null;

    Runnable runnable = new CountDownRunner();
            myThread = new Thread( runnable );
            myThread.start();



    class CountDownRunner implements Runnable
       {
          // @Override
           public void run()
            {
              while( !Thread.currentThread().isInterrupted() )
               {
                 try
                 {
                    navigation(); // do the work here 
                    Thread.sleep( 2000 );  // time interval for the counter. it will run every 2 sec
                }
                catch( InterruptedException e )
                {
                    Thread.currentThread().interrupt();
                }
                catch( Exception e )
                {
                }
            }
        }
    }

   public void navigation(Coordinate userPosition , Coordinate destination){
     if (Math.abs(userPosition.y - destination.y) > 500) {
     {Toast.makeText(this, "Walk for " + Math.abs(CheckPoint.y - UserPosition.y) + "mm", Toast.LENGTH_SHORT).show(); }
 }

Answer 4

也许有一个循环Thread？试试吧：

private Thread loopThread = new Thread(new Runnable() {
    public void run() {
       while(true){
          try {
              runOnUiThread(new Runnable() {
                 @Override
                 public void run() {
                     Toast.makeText(this, "Your text!", Toast.LENGTH_SHORT).show();
              });   
              Thread.Sleep(5000); //Wait 5 seconds, then repeat!     
           }catch (Exception e) {
                  return;
           }catch (InterruptedException i) {
                  return;
           }
        }
    }
});

然后在任意位置启动Thread：

Thread myThread = new Thread(loopThread);
myThread.start();

然后停止：

myThread.interrupt();

希望它有所帮助！

每隔X秒祝酒

4 个答案: