Question

我的SELECT查询中遇到GROUP BY和DATEADD的问题，它是这样的：（请参阅下面的示例sql代码）

SELECT 
    'USER1' AS [user_id],
    DATEADD(hh,-15,log_date) AS [LogDate],
    MIN(DATEADD(hh,-15,login_time)) AS [Login],
    MAX(DATEADD(hh,-15,logout_time)) AS [Logout],
    DATEDIFF(MINUTE,MIN(DATEADD(hh,-15,login_time)),
    MAX(DATEADD(hh,-15,logout_time)))/60.0  AS [TotalHrs]
FROM 
    tblDTR
WHERE 
    user_id = 'USER1' 
    AND log_date BETWEEN CAST('02/07/2014' AS datetime) 
                     AND CAST('02/28/2014' AS datetime)
GROUP BY 
    user_id,
    DATEADD(hh, -15, log_date)
ORDER BY 
    LogDate ASC

这就是结果：

enter image description here

我想要做的是LogDate列必须显示 REAL DATE＆amp; TIME （意味着，列不得减去 -15 ），以及正如您在LogDate列上方的结果表中看到的那样，虽然我使用GROUP BY DATEADD(hh, -15, log_date)但它根本不起作用。我错过了SQL代码的某些功能吗？

这是我的新SQL代码，用于显示LogDate而减去15 ：

SELECT 
    'USER1' AS [user_id],
    CONVERT(varchar,log_date,101) AS [LogDate], <-- I changed here but it didn't work, it give me error.
    MIN(DATEADD(hh, -15, login_time)) AS [Login],
    MAX(DATEADD(hh, -15, logout_time)) AS [Logout],
    DATEDIFF(MINUTE, MIN(DATEADD(hh, -15, login_time)),
    MAX(DATEADD(hh, -15, logout_time)))/60.0  AS [TotalHrs]
FROM 
    tblDTR
WHERE 
    user_id = 'USER1' 
    AND log_date BETWEEN CAST('02/07/2014' AS datetime) 
                     AND CAST('02/28/2014' AS datetime)
GROUP BY 
    user_id,
    DATEADD(hh, -15, log_date)
ORDER BY 
    LogDate ASC

错误：

Msg 8120，Level 16，State 1，Line 3
专栏＆＃39; tblDTR.log_date＆＃39;在选择列表中无效，因为它不包含在聚合函数或GROUP BY子句中。

非常感谢任何替代方案和建议。谢谢！

修改顺便说一下，我使用的是SQL Server 2012

输出必须：

-------------------------------------------------------------------------
| user_id |   LogDate  |       Login      |      LogOut      | TotalHrs |
-------------------------------------------------------------------------
|  USER1  | 02/07/2014 | 2014-02-07 08:12 | 2014-02-07 19:30 |   11.28  |
-------------------------------------------------------------------------

Answer 1

你可以简单地用另一个选择包裹你的选择，加上15个小时：

SELECT [user_id],
    DATEADD(hh, 15 ,LogDate) AS [LogDate],
    [Login],
    [Logout],
    [TotalHrs]
FROM (
    SELECT 
    'USER1' AS [user_id],
    DATEADD(hh,-15,log_date) AS [LogDate],
    MIN(DATEADD(hh,-15,login_time)) AS [Login],
    MAX(DATEADD(hh,-15,logout_time)) AS [Logout],
    DATEDIFF(MINUTE,MIN(DATEADD(hh,-15,login_time)),
                    MAX(DATEADD(hh,-15,logout_time)))/60.0  AS [TotalHrs]
    FROM tblDTR
    WHERE user_id = 'USER1' 
        AND log_date
            BETWEEN CAST('02/07/2014' AS datetime) 
                AND CAST('02/28/2014' AS datetime)
    GROUP BY 
        user_id,
        DATEADD(hh,-15,log_date)
) InnerQueryAlias
    ORDER BY LogDate ASC

Answer 2

在查询的GROUP BY子句中，替换

DATEADD(hh,-15,log_date)

带

tblDTR.log_date

SQL Server：group by和DATEADD混淆

2 个答案: