Question

我正在尝试通过提到的方法生成超链接 http://www.yiiframework.com/doc-2.0/guide-helper-html.html#hyperlinks喜欢这个

 Html::a('<b>Register</b>', 
    ['story/create', array('id' =>39,'usr'=>'11')], 
    ['class' => 'profile-link'])

我希望得到像story/create/id/39/usr/11

这样的网址

但它正在生成

story/create?1%5Bid%5D=39&1%5Busr%5D=1

我启用了yii2的干净网址功能，如

  'urlManager' => [
        'class' => 'yii\web\UrlManager',
        // Disable index.php
        'showScriptName' => false,
        // Disable r= routes
        'enablePrettyUrl' => true,
        'rules' => array(
                '<controller:\w+>/<id:\d+>' => '<controller>/view',
                '<controller:\w+>/<action:\w+>/<id:\d+>' => '<controller>/<action>',
                '<controller:\w+>/<action:\w+>' => '<controller>/<action>',
        ),
        ], also.

如何实现这一目标？

Answer 1

使用生成url使用（请参阅更多http://www.yiiframework.com/doc-2.0/guide-helper-url.html）：

Html::a('<b>Register</b>', 
        ['story/create', 'id' =>39,'usr'=>'11'], 
        ['class' => 'profile-link'])

在urlManager中输入新规则：

rules' => array(
  ....
  'story/create/<id:\d+>/<usr:\d+>' => 'story/create',

        ),

输出网址将是这样的：

story/create/39/11

在控制器中：

public function actionCreate($id, $usr)

Yii2提供此参数。

Answer 2

动态创建网址

Html::a('<b>Register</b>', 
    ['story/create', 'id' =>39,'usr'=>'11'], 
    ['class' => 'profile-link'])

在urlManager配置规则中：

'urlManager' => [
        'enablePrettyUrl' => true,
        'showScriptName' => false,
        'rules' => [
             '<controller:\w+>/<id:\d+>' => '<controller>/view',            
             '<controller:\w+>/<action:\w+>/<id:\d+>/<usr:\d+>' => '<controller>/<action>', 
        ],
    ],

输出网址将是这样的：

story/create/39/11

Answer 3

另一种有用的方法：

在

中写入urlManager规则

CREATE PROCEDURE [dbo].[set_member_email_to_read]

@member_email_id int,
@member_email_FK_message_id int,
@member_email_FK_user_id int
@member_email_status varchar(1),
@member_email_read_datetime dateTime,
@member_email_delete_datetime dateTime

as
if not exists (Select * from [dbo].[Member_email_read] where [member_email_FK_message_id] = @member_email_FK_message_id) begin
insert into [dbo].[Member_email_read]
    (
       [member_email_FK_message_id]
      ,[member_email_FK_user_id]
      ,[member_email_status]
      ,[member_email_read_datetime]
      ,[member_email_delete_datetime]
  )
  values
  (
        @member_email_FK_message_id,
        @member_email_FK_user_id
        @member_email_status,
        @member_email_read_datetime,
        @member_email_delete_datetime
  )


SELECT Convert(int,SCOPE_IDENTITY()) As InsertedID

end else begin
    update [dbo].[Member_email_read] set
   [member_email_FK_message_id]         =   @member_email_FK_message_id
  ,[member_email_FK_user_id]            =   @member_email_FK_user_id
  ,[member_email_status]                =   @member_email_status
  ,[member_email_read_datetime]         =   @member_email_read_datetime
  ,[member_email_delete_datetime]       =   @member_email_delete_datetime

where [member_email_FK_user_id] = @member_email_FK_user_id
if (@@ERROR = 0) begin
    SELECT Convert(int,@member_email_FK_user_id) As InsertedID
end
end
GO

可以在url controller / action / 100/20

中访问

使用干净的URL在yii2中的超链接中传递多个参数，Html :: a（）不会生成干净的URL

3 个答案: