我希望你们都过得愉快。我希望我可以通过我的项目代码获得一些帮助。基本上是一句话“淡出了”。输入时键入，然后输入搜索词“FADED”并执行代码以查看单词“FADED”是否在句子中，如果是，则会显示“x Match（es）Found”，如果不是“找不到匹配”。好吧，当我编译并运行它时，给我一个“第65行：运行时异常在0x00400098：地址超出范围0x00000000”错误，并且有多行有此错误。有人能帮我这个吗？过去3天我一直在尝试这样做，最后打破了一些帮助...如果您有任何疑问，请告诉我！
.data
str: .space 100 # Pre Allocate space for the input sentence
input: .space 30 # Pre Allocate space for the input sentence
ins: .asciiz "Please enter a sentence: " # string to print sentence
seek: .asciiz "Please enter a word: " # string to print sentence
nomatch: .asciiz "No Match(es) Found"
found: .asciiz " Match(es) Found"
newline: .asciiz "\n" # string to print newline
.text
li $v0, 4 # syscall to print string
la $a0, ins # move str into a0
syscall # syscall
li $a1, 100 # allocate space for the string
la $a0, str # load address of the input string
li, $v0, 8 # read string input from user
syscall # issue a system call
move $t9, $a0 # move string to t5
li $v0, 4 # syscall to print string
la $a0, seek # move str into a0
syscall # syscall
la $a0, input # load address of the input string
li $a2, 30 # allocate space for the string
li, $v0, 8 # read string input from user
syscall # issue a system call
move $t8, $a0 # move string to t8
la $s5, input # create space for the input word we are looking for in s5
wloop: # loop to allocate space for the word we are looking for to a register
lb $t0, 0($t8) # load first character into t0
beqz $t0, sentence # branch to sentence loop if null character
sb $t0, 0($s5) # store the current character into current address of s5
addi $t8, $t8, 1 # add one to t8 to move to next character
addi $s5, $s5, 1 # add one to s5 to move to the next allocated space
j wloop # jump back to wloop
la $s4, str # create space for the input sentence
sentence: # loop to allocate space for the word we are looking for into a register
lb $t0, 0($t9) # load first character into t0
beqz $t0, resetsen # branch to check loop if null character
sb $t9, 0($s4) # store the current character into current address of s4
addi $t9, $t9, 1 # add one to t9 to move to next character
addi $s4, $s4, 1 # add one to s5 to move to the next allocated space
j sentence # jump back to sentence
resetsen:
li $s4, 0 # reset sentence back to 0 (first character)
resetword:
li $s5, 0 # reset word we are looking for back to 0 (first character)
check:
lb $t1, 0($s4) # load current character of sentence to t1
beq $t1, 46, quit # branch to QUIT if period found
bne $t1, 70, nextword # if t1 != t0 branch to nextword
beq $t1, 70, checkword # branch to found if t1 = f
nextword: # loop to get to the next word
lb $t1, 0($s4) # load current character to t1
beq $t1, 46, quit # branch to quit if period found
bne $t1, 32, increment # if current character is not a spaace branch to increment
beq $t1, 32, plusone # if current character is a space branch to plusone
increment: # increment procedure
addi $s4, $s4, 1 # add one to s4 to move to next character
j nextword # jump to nextword
plusone: # plusone procedure
addi $s4, $s4, 1 # add one to s4 to move to next character
j resetword # jump to check
checkword:
addi $s4, $s4, 1 # add one to s4 to move to next character
addi $s5, $s5, 1 # add one to s5 to move to next character
lb $t1, 0($s4) # load current character of sentence to t1
lb $t0, 0($s5) # load current character of sentence to t0
bne $t1, $t0, increment # if t0 != t1 branch to increment (looking for a)
addi $s4, $s4, 1 # add one to s4 to move to next character
addi $s5, $s5, 1 # add one to s5 to move to next character
lb $t1, 0($s4) # load current character of sentence to t1
lb $t0, 0($s5) # load current character of sentence to t0
bne $t1, $t0, increment # if t0 != t1 branch to increment (looking for d)
addi $s4, $s4, 1 # add one to s4 to move to next character
addi $s5, $s5, 1 # add one to s5 to move to next character
lb $t1, 0($s4) # load current character of sentence to t1
lb $t0, 0($s5) # load current character of sentence to t0
bne $t1, $t0, increment # if t0 != t1 branch to increment (looking for e)
addi $s4, $s4, 1 # add one to s4 to move to next character
addi $s5, $s5, 1 # add one to s5 to move to next character
lb $t1, 0($s4) # load current character of sentence to t1
lb $t0, 0($s5) # load current character of sentence to t0
bne $t1, $t0, increment # if t0 != t1 branch to increment (looking for d)
addi $t2, $t2, 1 # add one to t2 which counts occurences
j resetword
quit:
beqz $t2, exit # if t2 = 0 branch to exit
li $v0, 1 # syscall to print integer
move $a0, $t2 # move str into a0
syscall # syscall
li $v0, 4 # syscall to print string
la $a0, found # move found into a0
syscall # syscall
j endprogram
exit:
li $v0, 4 # syscall to print string
la $a0, nomatch # move nomatch into a0
syscall # syscall
endprogram:
li $v0, 10
syscall