Question

运行以下代码允许3个方格围绕屏幕移动，然后假设自由漫游，从边缘反弹，直到遇到蓝线。他们也有严格的命令来反弹这条线。我可以做到这一点，当块来自右侧并从线的右侧反弹，但不是从左侧反弹并从线的左侧反弹。有关详细信息，请参阅代码。

import pygame, sys, time
from pygame.locals import *

pygame.init()
WINDOWWIDTH = 200
WINDOWHEIGHT = 300
screen = pygame.display.set_mode((WINDOWWIDTH, WINDOWHEIGHT), 0, 32)
pygame.display.set_caption('Animation')

DOWNLEFT = 1
DOWNRIGHT = 3
UPLEFT = 7
UPRIGHT = 9

MOVESPEED = 1

BLACK = (0, 0, 0)
RED = (255, 0, 0)
GREEN = (0, 255, 0)
BLUE = (0, 0, 255)


b1 = {'rect':pygame.Rect(0, 50, 25, 25), 'color':RED, 'dir':DOWNRIGHT}
b2 = {'rect':pygame.Rect(0, 100, 25, 25), 'color':GREEN, 'dir':DOWNRIGHT}
b3 = {'rect':pygame.Rect(0, 150, 25, 25), 'color':BLUE, 'dir':DOWNRIGHT}
blocks = [b1, b2, b3]

while True:
    # check for the closing of the 'x' button
    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()
    screen.fill(BLACK)
    pygame.draw.line(screen,BLUE,(150,0),(150,150),5)


    for b in blocks:
        #moves the blocks
        if b['dir'] == DOWNLEFT:
            b['rect'].left -= MOVESPEED
            b['rect'].top += MOVESPEED
        if b['dir'] == DOWNRIGHT:
            b['rect'].left += MOVESPEED
            b['rect'].top += MOVESPEED
        if b['dir'] == UPLEFT:
            b['rect'].left -= MOVESPEED
            b['rect'].top -= MOVESPEED
        if b['dir'] == UPRIGHT:
            b['rect'].left += MOVESPEED
            b['rect'].top -= MOVESPEED

        # check if the block has move out of the window
        if b['rect'].top < 0:
            # block has moved past the top
            if b['dir'] == UPLEFT:
                b['dir'] = DOWNLEFT
            if b['dir'] == UPRIGHT:
                b['dir'] = DOWNRIGHT
        if b['rect'].bottom > WINDOWHEIGHT:
            # block has moved past the bottom
            if b['dir'] == DOWNLEFT:
                b['dir'] = UPLEFT
            if b['dir'] == DOWNRIGHT:
                b['dir'] = UPRIGHT
        if b['rect'].left < 0:
            # block has moved past the left side
            if b['dir'] == DOWNLEFT:
                b['dir'] = DOWNRIGHT
            if b['dir'] == UPLEFT:
                b['dir'] = UPRIGHT
        if b['rect'].right > WINDOWWIDTH:
            # block has moved past the right side
            if b['dir'] == DOWNRIGHT:
                b['dir'] = DOWNLEFT
            if b['dir'] == UPRIGHT:
                b['dir'] = UPLEFT
        if b['rect'].left < 150 and b['rect'].top > 0 and b['rect'].top < 150:
            if b['dir'] == DOWNLEFT:
                b['dir'] = DOWNRIGHT
            if b['dir'] == UPLEFT:
                b['dir'] = UPRIGHT
##        if b['rect'].right > 150 and b['rect'].top > 0 and b['rect'].top < 150:
##            if b['dir'] == DOWNLEFT:
##                b['dir'] = DOWNRIGHT
##            if b['dir'] == UPLEFT:
##                b['dir'] = UPRIGHT
        print(b['rect'].right)
        pygame.draw.rect(screen, b['color'], b['rect'])

    pygame.display.update()
    time.sleep(0.0001)

Answer 1

import pygame, sys, time
from pygame.locals import *

pygame.init()
WINDOWWIDTH = 200
WINDOWHEIGHT = 300
screen = pygame.display.set_mode((WINDOWWIDTH, WINDOWHEIGHT), 0, 32)
pygame.display.set_caption('Animation')

DOWNLEFT = 1
DOWNRIGHT = 3
UPLEFT = 7
UPRIGHT = 9

MOVESPEED = 1

BLACK = (0, 0, 0)
RED = (255, 0, 0)
GREEN = (0, 255, 0)
BLUE = (0, 0, 255)


b1 = {'rect':pygame.Rect(0, 50, 25, 25), 'color':RED, 'dir':DOWNRIGHT}
b2 = {'rect':pygame.Rect(0, 100, 25, 25), 'color':GREEN, 'dir':DOWNRIGHT}
b3 = {'rect':pygame.Rect(0, 150, 25, 25), 'color':BLUE, 'dir':DOWNRIGHT}
blocks = [b1, b2, b3]


while True:
# check for the closing of the 'x' button
    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()
    screen.fill(BLACK)
    pygame.draw.line(screen,BLUE,(150,0),(150,150),5)


    for b in blocks:
    #moves the blocks
        if b['dir'] == DOWNLEFT:
            b['rect'].left -= MOVESPEED
            b['rect'].top += MOVESPEED
        if b['dir'] == DOWNRIGHT:
            b['rect'].left += MOVESPEED
            b['rect'].top += MOVESPEED
        if b['dir'] == UPLEFT:
            b['rect'].left -= MOVESPEED
            b['rect'].top -= MOVESPEED
        if b['dir'] == UPRIGHT:
            b['rect'].left += MOVESPEED
            b['rect'].top -= MOVESPEED

    # check if the block has move out of the window
        if b['rect'].top < 0:
        # block has moved past the top
            if b['dir'] == UPLEFT:
                b['dir'] = DOWNLEFT
            if b['dir'] == UPRIGHT:
                b['dir'] = DOWNRIGHT
        if b['rect'].bottom > WINDOWHEIGHT:
        # block has moved past the bottom
            if b['dir'] == DOWNLEFT:
                b['dir'] = UPLEFT
            if b['dir'] == DOWNRIGHT:
                b['dir'] = UPRIGHT
        if b['rect'].left < 0:
        # block has moved past the left side
            if b['dir'] == DOWNLEFT:
                b['dir'] = DOWNRIGHT
            if b['dir'] == UPLEFT:
                b['dir'] = UPRIGHT
        if b['rect'].right > WINDOWWIDTH:
        # block has moved past the right side
            if b['dir'] == DOWNRIGHT:
                b['dir'] = DOWNLEFT
            if b['dir'] == UPRIGHT:
                b['dir'] = UPLEFT
        if b['dir'] == UPLEFT or b['dir'] == DOWNLEFT: # In this case it's rather easy to check for the exact conditions when direction changes should be made. Being the movement speed is only 1, at some point the b['rect'].right/left will be exactly 150. It's easier to check for that than deal with greater than less than problems which tend to only work for one way. If movement was higher than one you'd have to switch to short ranges instead.
            if b['rect'].left == 150 and b['rect'].top > 0 and b['rect'].top < 150:
                if b['dir'] == DOWNLEFT:
                    b['dir'] = DOWNRIGHT
                if b['dir'] == UPLEFT:
                    b['dir'] = UPRIGHT

        if b['dir'] == DOWNRIGHT or b['dir'] == UPRIGHT:
            if b['rect'].right == 150 and b['rect'].top < 150:
                if b['dir'] == DOWNRIGHT:
                    b['dir'] = DOWNLEFT
                if b['dir'] == UPRIGHT:
                    b['dir'] = UPLEFT
        print(b['rect'].right)
        pygame.draw.rect(screen, b['color'], b['rect'])

    pygame.display.update()
    time.sleep(0.00001)

这个更正的代码更像是你希望我的思考。

在pygame中使一个块从一条线上反弹

1 个答案: