尝试编译代码时包装器构建错误

时间:2015-03-24 20:10:25

标签: c#

好的,所以我完全重写了这个代码,试图让这个更简单。现在它告诉我“类型或命名空间定义,或期望的文件结束。我只能认为我的间距是关闭或我错过了一个括号,但当我尝试添加一个括号时,我得到相同的错误。我想做的就是为我的EXE创建一个简单的包装器,它非常令人沮丧。请尽可能查看我的代码并告诉我这里的错误。欢迎任何帮助...

using System.IO;
//using Resources.resx;

namespace EXE_program
{
   public class LaunchEXE
    {
       static void Main(string[] args)
       {
            string exeName = Path.Combine(Directory.GetCurrentDirectory(), "EntUpdate_v3.0.exe");
            string argsLin = "";
            int timeoutSeconds = 100;}

            internal static string Run(string exeName, string argsLine, int timeoutSeconds)
            {

                StreamReader outputStream = StreamReader.Null;
                string output = "";
                bool success = false;



                Process newProcess = new Process();
                newProcess.StartInfo.FileName = exeName;
                newProcess.StartInfo.Arguments = argsLine;
                newProcess.StartInfo.UseShellExecute = false;
                newProcess.StartInfo.CreateNoWindow = true; //The command line is supressed to keep the process in the background
                newProcess.StartInfo.RedirectStandardOutput = true;
                newProcess.Start();


            return "\t" + output; }


        }
    }
}

0 个答案:

没有答案