Question

# For updating the version!
version = "0.1"

# For game start!
from choice1 import choice1
# insert import functions from checkpoints choices here!

def gamemenu():
print("Welcome to the RTG!")
# Starts the game
print("1. START!")
# Goes to an earlier checkpoint
print("2. CHECKPOINTS!")
# Views the "about' page
print("3. ABOUT")
# Shows my website address!
print("4. INFO ABOUT CREATOR")
# Exits the game
print("5. EXIT")

# The user input!
option = input("Make your choice, buddy! "

if option == "1":
   choice1()
# elif option == "2":
# Not added yet
elif option == "3":
   print("Random Text RPG, version %s" % version)
   print("This is just a random game made by me for fun")
   print("Please dont't take offence :(")
elif option == "4":
   print("Made by Lightning Bolt."))
elif option == "5":
   break
else:
   print("ERROR: invalid option")
   menu()

menu()

大家好，

我是初学程序员，遇到了一个我无法解决的问题。当我在Python 3 shell中运行我的程序时，它表示无效语法并在第1行中标记“：”为红色，这意味着存在错误。对于所有其他if / else / ifelse语句，它不会说：语法无效。如果我删除了“：”，它会将choice1（）标记为红色，表示语法不正确，而它的缩进只有4个空格。

我真的不知道代码有什么问题，感谢任何帮助我的人！

这是截图：http://imgur.com/wuWMa0L（缩进等）

Answer 1

关闭从用户
删除elif option == "4"
删除break语句，那里没有循环

代码：

# For updating the version!
version = "0.1"

# For game start!
from choice1 import choice1
# insert import functions from checkpoints choices here!

def gamemenu():
    print("Welcome to the RTG!")
    # Starts the game
    print("1. START!")
    # Goes to an earlier checkpoint
    print("2. CHECKPOINTS!")
    # Views the "about' page
    print("3. ABOUT")
    # Shows my website address!
    print("4. INFO ABOUT CREATOR")
    # Exits the game
    print("5. EXIT")

    # The user input!
    option = input("Make your choice, buddy! ") #you missed a closing parenthesis here :D

    if option == "1":
        choice1()
    # elif option == "2":
    # Not added yet
    elif option == "3":
       print("Random Text RPG, version %s" % version)
       print("This is just a random game made by me for fun")
       print("Please dont't take offence :(")
    elif option == "4":
       print("Made by Lightning Bolt.") # there was an extra paren here
    elif option == "5":
       pass #as @Padraic mentioned, there should be no break statement
    else:
       print("ERROR: invalid option")
       menu()

menu()

这段代码有什么问题[Python]？

1 个答案: