我有一个包含最深层对象的多级数组。
[
[
[
"FUND",
{
"totassets":10.9,
"totdate":"2015-03-23",
"expratiogross":1.35,
"exprationet":1.08
}
],
[
"DAILY",
{
"navdate":"2015-03-23",
"nav":10.05,
"chgamt":0,
"chgpct":0,
"pop":10.05,
"ytdreturn":2.03,
"curr7dayyield":0,
"eff7dayyield":0,
"unsub7dayyield":0,
"30dayyield":0,
"30dayloadyield":0
}
]
]
]
我想使用ngRepeat显示" FUND"中的所有项目。或"每日"但我不确定如何深入访问这些对象而没有上面每个数组的名称。
很抱歉,如果这是一个基本问题,但我无法在其他地方找到答案。
答案 0 :(得分:1)
您想要获得两个外部数组的第一个元素。
$scope.obj = [
[
[
"FUND",
{
"totassets":10.9,
"totdate":"2015-03-23",
"expratiogross":1.35,
"exprationet":1.08
}
],
[
"DAILY",
{
"navdate":"2015-03-23",
"nav":10.05,
"chgamt":0,
"chgpct":0,
"pop":10.05,
"ytdreturn":2.03,
"curr7dayyield":0,
"eff7dayyield":0,
"unsub7dayyield":0,
"30dayyield":0,
"30dayloadyield":0
}
]
]
]
<ng-repeat el in obj[0][0]>
<span>totassets: {{el[0].FUND.totalAssets}}</span>
<span>navdate: {{el[0].DAILY.navdate}}</span>
</ng-repeat>
答案 1 :(得分:0)
你对数组的一个问题是,即使你忽略外部数组,你仍然会留下两个单独的数组a la:
[
"FUND",
{
"totassets":10.9,
"totdate":"2015-03-23",
"expratiogross":1.35,
"exprationet":1.08
}
],
和
[
"DAILY",
{
"navdate":"2015-03-23",
"nav":10.05,
"chgamt":0,
"chgpct":0,
"pop":10.05,
"ytdreturn":2.03,
"curr7dayyield":0,
"eff7dayyield":0,
"unsub7dayyield":0,
"30dayyield":0,
"30dayloadyield":0
}
]
因此,您需要两个ngRepeat
块来实现我想要实现的目标,并且更深层次以实际访问您想要的值。
这是一个快速的plnkr来展示我的意思:http://plnkr.co/edit/ArCh8q8w2JoXsg107XwP?p=preview