所以基本上在改变了我的一个老问题，例如2000万次之后，我终于找到了如何将我的两个变量分开并将它们匹配在一起，或者至少我认为我有。
我的代码基本上取自1和2的列表，然后根据是否分配了一个或两个来决定，如果玩家获得描绘某些内容的图片或描绘文本的图片，则相应地选择它们从列表和标记。
然而，当我为AssigningPicturesToPictureBoxes（）运行我的方法时，抛出了ArgumentOutOfRangeException并且我无法理解为什么，因为每当调用整数列表图片时它都不会发生，但每当整数列表时它确实会引起问题文本被称为。由于这两组代码实际上是相同的，我无法理解我的生活中有什么问题。如果有人能帮助我，我真的很感激。
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
using System.IO;
namespace BinaryFileReader
{
public partial class Form2 : Form
{
public Form2()
{
InitializeComponent();
AssignTorPToPictureBoxes();
AssignPicturesToPictureBoxes();
}
Random random = new Random();
List<int> pictures = new List<int>()
{
1,2,3,4,5,6,7,8
};
List<int> texts = new List<int>()
{
1,2,3,4,5,6,7,8
};
List<int> TorP = new List<int>()
{
1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2
};
private void AssignPicturesToPictureBoxes()
{
foreach(Control Control in tableLayoutPanel1.Controls)
{
PictureBox picturebox = Control as PictureBox;
if (picturebox.Tag.ToString() == "1")
{
int randomNumber = random.Next(pictures.Count);
int unconvertedtag = pictures[randomNumber];
string convertedtag = unconvertedtag.ToString();
picturebox.Tag = convertedtag;
picturebox.Visible = false;
pictures.RemoveAt(randomNumber);
if (picturebox.Tag.ToString() == "1")
{
picturebox.Image = global::BinaryFileReader.Properties.Resources.BSLSIGNA;
}
if (picturebox.Tag.ToString() == "2")
{
picturebox.Image = global::BinaryFileReader.Properties.Resources.BSLSIGNBREAKFAST;
}
if (picturebox.Tag.ToString() == "3")
{
picturebox.Image = global::BinaryFileReader.Properties.Resources.BSLSIGNCAR;
}
if (picturebox.Tag.ToString() == "4")
{
picturebox.Image = global::BinaryFileReader.Properties.Resources.BSLSIGNCAT;
}
if (picturebox.Tag.ToString() == "5")
{
picturebox.Image = global::BinaryFileReader.Properties.Resources.BSLSIGNCOFFEE;
}
if (picturebox.Tag.ToString() == "6")
{
picturebox.Image = global::BinaryFileReader.Properties.Resources.BSLSIGNDOG;
}
if (picturebox.Tag.ToString() == "7")
{
picturebox.Image = global::BinaryFileReader.Properties.Resources.BSLSIGNENGLAND;
}
if (picturebox.Tag.ToString() == "8")
{
picturebox.Image = global::BinaryFileReader.Properties.Resources.BSLSIGNH;
}
}
if (picturebox.Tag.ToString() == "2")
{
int randomNumber = random.Next(texts.Count);
int unconvertedtag = texts[randomNumber];
string convertedtag = unconvertedtag.ToString();
picturebox.Tag = convertedtag;
picturebox.Visible = false;
texts.RemoveAt(randomNumber);
if (picturebox.Tag.ToString() == "1")
{
picturebox.Image = global::BinaryFileReader.Properties.Resources.BSLTEXTA;
}
if (picturebox.Tag.ToString() == "2")
{
picturebox.Image = global::BinaryFileReader.Properties.Resources.BSLTEXTBREAKFAST;
}
if (picturebox.Tag.ToString() == "3")
{
picturebox.Image = global::BinaryFileReader.Properties.Resources.BSLTEXTCAR;
}
if (picturebox.Tag.ToString() == "4")
{
picturebox.Image = global::BinaryFileReader.Properties.Resources.BSLTEXTCAT;
}
if (picturebox.Tag.ToString() == "5")
{
picturebox.Image = global::BinaryFileReader.Properties.Resources.BSLTEXTCOFEE;
}
if (picturebox.Tag.ToString() == "6")
{
picturebox.Image = global::BinaryFileReader.Properties.Resources.BSLTEXTDOG;
}
if (picturebox.Tag.ToString() == "7")
{
picturebox.Image = global::BinaryFileReader.Properties.Resources.BSLTEXTENGLAND;
}
if (picturebox.Tag.ToString() == "8")
{
picturebox.Image = global::BinaryFileReader.Properties.Resources.BSLTEXTH;
}
}
}
}
private void AssignTorPToPictureBoxes()
{
foreach (Control Control in tableLayoutPanel1.Controls)
{
PictureBox picturebox = Control as PictureBox;
if (picturebox != null)
{
int randomNumber = random.Next(TorP.Count);
int unconvertedtag = TorP[randomNumber];
string convertedtag = unconvertedtag.ToString();
picturebox.Tag = convertedtag;
TorP.RemoveAt(randomNumber);
}
}
}
private void pictureBox1_Click(object sender, EventArgs e)
{
PictureBox picturebox = sender as PictureBox;
if (picturebox != null)
{
if (picturebox.Visible == true)
{
return;
}
else
{
picturebox.Visible = true;
}
}
}
}
}
在旁注中，任何人都想知道为什么我这样做的原则，这是一个游戏，其中玩家点击一个图片框，他们点击另一个图片框并尝试将它们匹配在一起在一个时间限制内，很遗憾，这是该计划目前唯一没有工作的部分。
编辑：对不起，我不够具体，我只会在一秒钟内获得特定部分
EDIT2： 错误特别出现在
部分int unsvertedtag = text [randomNumber];
Random random = new Random();
List<int> pictures = new List<int>()
{
1,2,3,4,5,6,7,8
};
List<int> texts = new List<int>()
{
1,2,3,4,5,6,7,8
};
List<int> TorP = new List<int>()
{
1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2
};
private void AssignPicturesToPictureBoxes()
{
foreach(Control Control in tableLayoutPanel1.Controls)
{
PictureBox picturebox = Control as PictureBox;
if (picturebox.Tag.ToString() == "1")
{
int randomNumber = random.Next(pictures.Count);
int unconvertedtag = pictures[randomNumber];
string convertedtag = unconvertedtag.ToString();
picturebox.Tag = convertedtag;
picturebox.Visible = false;
pictures.RemoveAt(randomNumber);
}
if (picturebox.Tag.ToString() == "2")
{
int randomNumber = random.Next(texts.Count);
int unconvertedtag = texts[randomNumber];
string convertedtag = unconvertedtag.ToString();
picturebox.Tag = convertedtag;
picturebox.Visible = false;
texts.RemoveAt(randomNumber);
}