我正在开发TAI
,它必须在WebSphere Portal中授权用户。
我的TAI
使用OpenID
Connect获取有关用户的所有信息,我想构建一些上下文,将其提供给WAS并告诉WAS他必须信任此环境而无需本地帐户。
如何在本地存储库中没有用户帐户的TAI
中授权用户?
更新:
代码:
String userid = "bob";
String uniqueid = "bob";
Hashtable hashtable = new Hashtable();
hashtable.put(AttributeNameConstants.WSCREDENTIAL_UNIQUEID, uniqueid);
hashtable.put(AttributeNameConstants.WSCREDENTIAL_SECURITYNAME, userid);
hashtable.put(AttributeNameConstants.WSCREDENTIAL_CACHE_KEY, uniqueid+"MyCustom");
Subject subject = new Subject();
subject.getPublicCredentials().add(hashtable);
return TAIResult.create(HttpServletResponse.SC_OK, "ignored", subject);
日志:
[25.03.15 20:16:33:521 AMT] 00000043 ServiceLogger I com.ibm.ws.ffdc.IncidentStreamImpl initialize FFDC0009I: FFDC opened incident stream file WebSphere_Portal_00000043_15.03.25_20.16.33_0.txt
[25.03.15 20:16:33:537 AMT] 00000043 ServiceLogger I com.ibm.ws.ffdc.IncidentStreamImpl resetIncidentStream FFDC0010I: FFDC closed incident stream file WebSphere_Portal_00000043_15.03.25_20.16.33_0.txt
[25.03.15 20:16:33:677 AMT] 00000043 StorageApi E com.ibm.wps.policy.commands.StorageApi StorageApi EJQAB0064E: A Null argument was passed to the StorageApi constructor.
[25.03.15 20:16:33:724 AMT] 00000043 PolicyService E com.ibm.wps.policy.services.PolicyService Error Occured while creating storageAPI EJQAB0064E: A Null argument was passed to the StorageApi constructor.
FFDC
------Start of DE processing------ = [3/25/15 20:16:33:474 AMT] , key = com.ibm.websphere.wim.exception.PropertyNotDefinedException com.ibm.ws.security.auth.ContextManagerImpl.runAs 4153
Exception = com.ibm.websphere.wim.exception.PropertyNotDefinedException
Source = com.ibm.ws.security.auth.ContextManagerImpl.runAs
probeid = 4153
Stack Dump = com.ibm.websphere.wim.exception.PropertyNotDefinedException: CWWIM0514W The 'dn' property is not defined.
对于此错误,我找到this information。
但我不明白他们要我做......
说明
我有FederatedRepositories只有一个LDAP存储库。
更新#2:
我在WAS 8.5.5.2上制作了这样的TAI并且没有错误,只有白屏。我尝试使用组“wpsadmins”授权用户“bob”。有一个带有一个基于文件的内置存储库的FederatedRepositories。
更新#3:
我为WAS编写了自定义应用程序,其中有一个按钮,它向Servlet发出POST请求。
部分代码:
if (req.getRemoteUser() == null) {
req
.setAttribute("errorMessage",
"<b>Error: Please log in before accessing PrintUserInfo.<b>");
RequestDispatcher disp = getServletContext().getRequestDispatcher(
"/login.jsp");
disp.forward(req, resp);
return;
}
resp.setContentType("text/html");
PrintWriter out = new PrintWriter(resp.getOutputStream());
String id = WSSubject.getCallerPrincipal();
out.println("The WAS Subject layer thinks you are " + id);
Context ic = new InitialContext();
Object objRef = ic.lookup("UserRegistry");
UserRegistry userReg = (UserRegistry) PortableRemoteObject.narrow(
objRef, UserRegistry.class);
out.println("<BR><BR>The user registry says your display name is: "
+ userReg.getUserDisplayName(req.getUserPrincipal()
.getName()));
Subject subject = WSSubject.getCallerSubject();
Set credSet = subject.getPublicCredentials(WSCredential.class);
//should be impossible.
if (credSet.size() > 1) {
System.out
.println("Expected only one WSCredential in Subject set");
throw new Exception("Expected one WSCredential, found "
+ credSet.size());
}
if (credSet.isEmpty()) {
System.out.println("Credential set is empty");
throw new Exception("Found no credentials");
}
//get one and only one element of Set
Iterator iter = credSet.iterator();
WSCredential creds = (WSCredential) iter.next();
out.println("<BR><BR>Looking into your Subject your userid is "
+ creds.getSecurityName());
out.println("<BR><BR>Looking into your Subject your uniqueid is "
+ creds.getUniqueSecurityName());
out
.println("<BR><BR>Looking into your Subject I see these groups: ");
//List groups = helper.getGroups();
List groups = creds.getGroupIds();
iter = groups.iterator();
while (iter.hasNext()) {
String gid = (String) iter.next();
out.println("<BR>Group ID: " + gid);
}
新版TAI:
String userid = "alisa";
String uniqueid = "bob";
// add admin group
// stash in hashtable
Hashtable hashtable = new Hashtable();
try {
InitialContext ctx = new InitialContext();
UserRegistry reg =(UserRegistry)ctx.lookup("UserRegistry");
String wpsadminsGroupUniqueId = reg.getUniqueGroupId("wpsadmins");
List<String> groups = new ArrayList<String>();
groups.add(wpsadminsGroupUniqueId);
hashtable.put(AttributeNameConstants.WSCREDENTIAL_GROUPS, groups);
} catch (Exception e) {
System.out.println("EXCEPTION IN TAI");
e.printStackTrace();
}
hashtable.put(AttributeNameConstants.WSCREDENTIAL_UNIQUEID,uniqueid);
hashtable.put(AttributeNameConstants.WSCREDENTIAL_SECURITYNAME,userid);
hashtable.put(AttributeNameConstants.WSCREDENTIAL_CACHE_KEY,uniqueid+"MyCustom");
Subject subject = new Subject();
subject.getPublicCredentials().add(hashtable);
return TAIResult.create(HttpServletResponse.SC_OK, "ignored", subject);
所以我从Subject获得了我的凭据,包括userId,uniqueId和来自LDAP的组。
结果:
The WAS Subject layer thinks you are alisa
The user registry says your display name is:
Looking into your Subject your userid is alisa
Looking into your Subject your uniqueid is bob
Looking into your Subject I see these groups:
Group ID: group:domain:port/cn=wpsadmins,cn=CN,ou=OU,o=O,o=O,c=ru
更新#4
我在TAI中添加了几个组,而不是我在Portal(我认为)中授权,但我只看到没有任何东西的白色屏幕。怎么了?
更新#5
而WPS给了我一个例外:
[26.03.15 18:47:41:006 AMT] 0000004e DefaultLoginF E com.ibm.wps.auth.impl.DefaultLoginFilter doLoginWithExceptions WpsException occured: com.ibm.wps.services.authentication.exceptions.UserRetrieveException: EJPSD0008E: Exception occurred while retrieving the user [null] from the user registry.
答案 0 :(得分:2)
您需要创建完整主题,有关详情,请查看Advanced authentication in WebSphere Application Server。
简而言之,您需要使用类似的代码:
String userid = "bob";//get from request
String uniqueid = "bob";
// stash in hashtable
Hashtable hashtable = new Hashtable();
hashtable.put(AttributeNameConstants.WSCREDENTIAL_UNIQUEID,uniqueid);
hashtable.put(AttributeNameConstants.WSCREDENTIAL_SECURITYNAME,userid);
// hashtable.put(AttributeNameConstants.WSCREDENTIAL_GROUPS,groups);
hashtable.put(AttributeNameConstants.WSCREDENTIAL_CACHE_KEY,uniqueid+"MyCustom");
Subject subject = new Subject();
subject.getPublicCredentials().add(hashtable);
return TAIResult.create(HttpServletResponse.SC_OK, "ignored", subject);
答案 1 :(得分:0)
在更新#5中添加的WPS异常 WebSphere Portal要求uniqueid是完全限定的DN。在你的情况下,你只有一个短名称。 Portal使用DN在VMM上查找用户,并期望WSCredential.getUniqueSecurityName()返回DN。