Question

我有两个表，每个表都有很多属性。我想从每个属性中获取属性，我正在尝试编写一个查询来获取这些属性，并将它们分成三列。

表A

LOCATION_NUMBER (varchar2(20Byte)), 
BEGIN (NUMBER (3,0)), 
BEGIN_DEC (NUMBER (4,3)), 
END (NUMBER (3,0)), 
END_DEC (NUMBER (4,3))

表B

LOCNUM (NUMBER (15,0)), 
START (VARCHAR2(6 BYTE)), 
START_POS (NUMBER (5,3)), 
FINISH (VARCHAR2 (6 BYTE)), 
FINISH_POS (NUMBER (5,3)).

我想从查询中得到的是一个表，它有三个属性，然后先按位置排序这些表，然后从第二个开始。

表C，

LOCATION, 
START, 
END

以下是一个例子：

A：

LOCATION_NUMBER    BEGIN    BEGIN_DEC    END    END_DEC
      I 26          8          0.63       13      0.99
      I 32          144        0          151     0.82
      I 35          22         0.29       55      0.09
      I 35          128        0.1        67      0.9
      I 35          0          0          22      0.28

B：

LOC_NUM            START    START_POS    FINISH  FINSIH_POS
      227           98         0.56       100     0
      35            149        0.25       151     0.55
      96            156        0.23       156     1.26
      11            263        2.56       263     4.52

结果集：

LOCATION       START        END
    26          8.63         13.99
    32          144          151.82
    35          22.29        55.09
    35          128.1        67.9
    35          0            22.28   
    227         98.56        100
    35          149.25       151.55
    96          156.23       157.26
    11          265.56       267.52

我有一些我尝试的查询我能够从每个表中获得所需的结果，我只需要知道如何将它们合并为一个，以便为我想要的表更容易，同样，每个表格中还有10到20个我不想担心的属性。

Select to_number(trim(regexp_substr(A.LOCATION_NUMBER ,'[^ ]+', 1, 2))) AS LOCATION,
(to_number(trim(A.BEGIN)) + to_number(trim(A.BEGIN_DEC))) AS START,
(to_number(trim(A.END)) + to_number(trim(A.END_DEC))) AS END
FROM A
ORDER BY to_number(trim(regexp_substr(A.LOCATION_NUMBER,'[^ ]+', 1, 2)));

SELECT B.LOC_NUM AS LOCATION,
(to_number(trim(B.START)) + to_number(trim(B.START_POS))) AS START,
(to_number(trim(B.FINISH)) + to_number(trim(B.FINISH_POS))) AS END
FROM B
ORDER BY B.LOCATION, START;

Answer 1

假设您的查询有效，您只需要union all：

Select to_number(trim(regexp_substr(A.LOCATION_NUMBER ,'[^ ]+', 1, 2))) AS LOCATION,
       to_number(trim(A.BEGIN)) + to_number(trim(A.BEGIN_DEC)) AS START,
       to_number(trim(A.END)) + to_number(trim(A.END_DEC)) AS END
FROM A
UNION ALL
SELECT B.LOC_NUM AS LOCATION,
       to_number(trim(B.START)) + to_number(trim(B.START_POS)) AS START,
       to_number(trim(B.FINISH)) + to_number(trim(B.FINISH_POS)) AS END
FROM B
ORDER BY B.LOCATION, START;

在Oracle SQL中将两个表合并为一个表

1 个答案: