Question

当我使用下面的函数时，它成功返回的唯一时间是我只对单个字符串使用它。如果我尝试在代码中针对不同的唯一字符串多次调用该函数，则会返回＆＃34;不可解析的日期＆＃34;错误。

function oraDate(str) {
    if(str.length > 0){
        channelMap.put("StringCount", str.length);
        if(str.length == 8){
            channelMap.put("8 characters", "Date only");
            var date = str.substring(0, 8);
            var cDate = DateUtil.convertDate("yyyyMMdd", "yyyy-MM-dd", date);
            return cDate + 'T' + '00:00:00';

        } else if(str.length == 12){
            channelMap.put("12 characters", "Date/time only");
            var date = str.substring(0, 8);
            var time = str.substring(8, 12);
            var cDate = DateUtil.convertDate("yyyyMMddHHmm", "yyyy-MM-dd'T'HH:mm", date);
            return cDate+':00';

        } else if(str.length >= 14){
            channelMap.put("14 characters", "Date/time w/seconds only");
            var date = str.substring(0, 8);
            var time = str.substring(8, 14);
            var date_time = date+time;
            var cDate = DateUtil.convertDate("yyyyMMddHHmmss", "yyyy-MM-dd'T'HH:mm:ss", date_time);
            return cDate;
        }

    } else {
        return '0001-01-01T00:00:00';   
    }
}

Answer 1

我忘了回到这里发布修复。我错过了＆＃34; date_time＆＃34; 12个字符检查的变量。

function oraDate(str) {
if(str.length > 0){
    channelMap.put("StringCount", str.length);
    if(str.length == 8){
        channelMap.put("8 characters", "Date only");
        var date = str.substring(0, 8);
        var cDate = DateUtil.convertDate("yyyyMMdd", "yyyy-MM-dd", date);
        return cDate + 'T' + '00:00:00';

    } else if(str.length == 12){
        channelMap.put("12 characters", "Date/time only");
        var date = str.substring(0, 8);
        var time = str.substring(8, 12);
        var date_time = date+time;
        var cDate = DateUtil.convertDate("yyyyMMddHHmm", "yyyy-MM-dd'T'HH:mm", date_time);
        return cDate+':00';

    } else if(str.length >= 14){
        channelMap.put("14 characters", "Date/time w/seconds only");
        var date = str.substring(0, 8);
        var time = str.substring(8, 14);
        var date_time = date+time;
        var cDate = DateUtil.convertDate("yyyyMMddHHmmss", "yyyy-MM-dd'T'HH:mm:ss", date_time);
        return cDate;
    }

} else {
    return '0001-01-01T00:00:00';
}

}

Javascript：函数仅在代码中使用单个实例时才能正常工作

1 个答案: