我的代码是:
<script type="text/javascript" src="http://ajax.googleapis.com/
ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function()
{
//bit_url function
function bit_url(url)
{
var url=url;
var username="username"; // bit.ly username
var key="bit.ly API key";
$.ajax({
url:"http://api.bit.ly/v3/shorten",
data:{longUrl:url,apiKey:key,login:username},
dataType:"jsonp",
success:function(v)
{
var bit_url=v.data.url;
$("#result").html('<a href="'+bit_url+'" target="_blank">'+bit_url+'</a>');
}
});
}
$("#short").click(function()
{
var url=$("#url").val();
var urlRegex = /(\b(https?|ftp|file):\/\/[-A-Z0-9+&@#\/%?=~_|!:,.;]*[-A-Z0-9+&@#\/%=~_|])/ig;
var urltest=urlRegex.test(url);
if(urltest)
{
bit_url(url);
}
else
{
alert("Bad URL");
}
});
});
</script>
//HTML Code
<input type="text" name="url" id="url"/>
<input type="submit" id="short" value="Submit"/>
<div id="result"></div>`enter code here`
当我给this url时,它既没有给出错误也没有给出短网址。请帮我找出解决此错误的方法。
提前谢谢!