如何在非zmq socket和pyzmq之间进行调整?

时间:2015-03-24 09:31:31

标签: python zeromq pyzmq

我想在非ZMQ套接字和ZMQ套接字之间编写一个桥接器。

客户代码:

import socket

if __name__ == '__main__':

    HOST = "localhost"
    PORT = 8888
    BUFFER = 4096

    try:
        sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
        print sock
        ret = sock.connect((HOST, PORT))
        print ret

        ret = sock.send('hello, tcpServer!')
        print ret
        recv = sock.recv(BUFFER)
        print ('[tcpServer siad]: %s' % recv)
        sock.close()
    except e:
        print e

代理代码,使用此代理向ZMQ_REP服务器发送请求。

import zmq

if __name__ == '__main__':

    context = zmq.Context()
    socket = context.socket(zmq.STREAM)
    socket.bind("tcp://*:8888")

    socket_req = context.socket(zmq.REQ)
    socket_req.connect("tcp://localhost:5556")

    while True:
        clientid, message = socket.recv_multipart();

        print("id: %r" % clientid)
        print("request:",message.decode('utf8'))

        socket_req.send(clientid, flags=zmq.SNDMORE, copy=False)
        socket_req.send("Hi", copy=False)

        clientid, message = socket_req.recv_multipart()


        print("id: %r" % clientid)
        print("request:",message.decode('utf8'))

ZMQ_REP服务器代码:

import zmq
import time
import sys


if __name__ == '__main__':

    port = '5556'
    if len(sys.argv) > 1:
        port = sys.argv[1]
        int(port)

    context = zmq.Context()
    socket = context.socket(zmq.REP)
    socket.bind("tcp://*:%s" % port)

    while True:
        message = socket.recv()
        print "Received request: ", message
        time.sleep(1)
        socket.send("world from %s" % port)

REQ获取错误:

Received request:  k
Traceback (most recent call last):
  File "req_server.py", line 21, in <module>
    socket.send("world from %s" % port)
  File "zmq/backend/cython/socket.pyx", line 574, in zmq.backend.cython.socket.Socket.send (zmq/backend/cython/socket.c:5434)
  File "zmq/backend/cython/socket.pyx", line 621, in zmq.backend.cython.socket.Socket.send (zmq/backend/cython/socket.c:5196)
  File "zmq/backend/cython/socket.pyx", line 181, in zmq.backend.cython.socket._send_copy (zmq/backend/cython/socket.c:2035)
  File "zmq/backend/cython/checkrc.pxd", line 21, in zmq.backend.cython.checkrc._check_rc (zmq/backend/cython/socket.c:6248)
zmq.error.ZMQError: Operation cannot be accomplished in current state

2 个答案:

答案 0 :(得分:5)

第一点:一般不建议在zmq中使用REQ / REP。使用更一般的DEALER / ROUTER组合。唯一的区别是:

  1. 当ROUTER收回时,路由ID是邮件的第一部分。这用于将回复路由回发件人。
  2. 未强制执行lock-step req / rep / req / rep序列(这是您看到的错误)。
  3. 以下是使用经销商的代理版本:

    import zmq
    
    if __name__ == '__main__':
    
        context = zmq.Context()
        socket = context.socket(zmq.STREAM)
        socket.bind("tcp://*:8888")
    
        socket_req = context.socket(zmq.DEALER)
        socket_req.connect("tcp://localhost:5556")
    
        while True:
            clientid, message = socket.recv_multipart()
    
            print("id: %r" % clientid)
            print("request: %s" % message.decode('utf8'))
    
            socket_req.send(message)
    
            reply = socket_req.recv()
            print("reply: %s" % reply.decode('utf8'))
    
            socket.send_multipart([clientid, reply])
    

    您的服务器,使用ROUTER:

    import zmq
    import time
    import sys
    
    
    if __name__ == '__main__':
    
        port = 5556
        if len(sys.argv) > 1:
            port = int(sys.argv[1])
    
        context = zmq.Context()
        socket = context.socket(zmq.ROUTER)
        socket.bind("tcp://127.0.0.1:%i" % port)
    
        while True:
            message = socket.recv_multipart()
            req_id = message[0]
            print("Received request: %s" % message[1:])
            time.sleep(1)
            socket.send_multipart([req_id, "world from %s" % port])
    

答案 1 :(得分:0)

socket_req.send(clientid, flags=zmq.SNDMORE, copy=False)
socket_req.send("Hi", copy=False)

最好的猜测是它没有正确注册SNDMORE标志并尝试发送一个全新的请求而不是附加到第一个请求(从而打破了REQ套接字的严格SEND / RECEIVE命令)...因此&#34;当前状态&#34;套接字不允许它发送消息的第二部分。尝试使用send_multipart(),或验证您的参数是否正确传递。