Question

1）使用json从netbeans实现web服务，该服务从MySQL数据库中获取数据

2）在android中创建rest客户端以调用web服务

已编辑的代码

我的清单文件

    <application
        android:allowBackup="true"
        android:icon="@drawable/ic_launcher"
        android:label="@string/app_name"
        android:theme="@style/AppTheme" >

        <uses-permission android:name="android.permission.INTERNET"/>
        <uses-permission android:name="android.permission.ACCESS_NETWORK_STATE"/>

        <activity
            android:name=".MainActivity"
            android:label="@string/app_name" >
            <intent-filter>
                <action android:name="android.intent.action.MAIN" />

                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>
        </activity>
    </application>

</manifest>

jsonParse.java

package android.project.srt.demojson;

public class JsonParser {

 static InputStream is = null;
static JSONObject jObj = null;
static String json = "";

// constructor
public JsonParser() {
}

public String getJSONFromUrl(String url) {
    // Making HTTP request
    try {
        HttpGet get = new HttpGet(url);
        HttpClient client = new DefaultHttpClient();
        HttpResponse response = client.execute(get);
        HttpEntity entity = response.getEntity();

        InputStream inputStream=entity.getContent();
        BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream),8 * 1024);

        String line=null;
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
    inputStream.close();
    } catch (UnsupportedEncodingException e) {
        Log.e("unsupported ","encoding exception" +e.getMessage());
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        Log.e("clientprotocolexception ","" + e.getMessage());
        e.printStackTrace();
    } catch (IOException e) {
        Log.e("io","Exception " + e.getMessage());
        e.printStackTrace();
    }

    return sb.toString();
}
}

MainActivity.java

public class MainActivity extends ActionBarActivity {

private static String url = "http://192.168.1.31:8084/adminWebservice/mywebservice/SelectRestroTypes";
String categoryname;
TextView tv1;

@Override
protected void onCreate(Bundle savedInstanceState) {
     super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    tv1 = (TextView) findViewById(R.id.textView1);

    //new JSONParse().execute();

    pDialog = new ProgressDialog(MainActivity.this);
    pDialog.setMessage("Loading Data ...");
    pDialog.setIndeterminate(false);
    pDialog.setCancelable(true);
    pDialog.show();
    tv1.setText("Getting Values Pls wait..");

    JsonParser jParser = new JsonParser();
    // Getting JSON from URL
//    JSONObject json = jParser.getJSONFromUrl(url);

    String jsonString=jParser.getJSONFromUrl(url);
    tv1.setText(jsonString);
}    
}

logcat显示了这个唯一的错误：

03-24 19:11:20.914  30629-30629/android.project.srt.demojson E/ViewRootImpl﹕ sendUserActionEvent() mView == null

欢迎任何有关在Android中创建json客户端的建议

提前感谢您的帮助

Answer 1

似乎这是你的问题

与http://localhost:8084拒绝的例外情况

在android中创建REST客户端时出错

1 个答案: