我有两个数据库。一个oracle和一个sql server。 对于oracle。
WITH cycleset AS (
SELECT
c.CYCLE_OID
, UPPER(m.NAME) AS MACHINE_NAME, c.PAYLOAD
FROM mshist.CYCLE c
INNER JOIN msmodel.MACHINE m ON m.machine_oid = c.primarymachine
WHERE (c.CYCLE_OID BETWEEN 1705497113111 AND 1705497596716)),
eventset AS (
SELECT cs.* ,
CAST((
EXTRACT(SECOND FROM ( a.END_TIME_UTC - a.START_TIME_UTC) DAY TO SECOND) +
EXTRACT(MINUTE FROM ( a.END_TIME_UTC- a.START_TIME_UTC) DAY TO SECOND) * 60 +
EXTRACT(HOUR FROM ( a.END_TIME_UTC - a.START_TIME_UTC) DAY TO SECOND) * 60 * 60 +
EXTRACT(DAY FROM ( a.END_TIME_UTC - a.START_TIME_UTC) DAY TO SECOND) * 60 * 60 * 24
) AS NUMBER(19,0)) AS DURATION
FROM cycleset cs
INNER JOIN mshist.CYCLEACTIVITYCOMPONENT a ON cs.CYCLE_OID = a.OID
WHERE a.NAME NOT IN ('Machine.Delay')
UNION ALL
SELECT cs.* ,
CAST((
EXTRACT(SECOND FROM ( a.END_TIME_UTC - a.START_TIME_UTC) DAY TO SECOND) +
EXTRACT(MINUTE FROM ( a.END_TIME_UTC- a.START_TIME_UTC) DAY TO SECOND) * 60 +
EXTRACT(HOUR FROM ( a.END_TIME_UTC - a.START_TIME_UTC) DAY TO SECOND) * 60 * 60 +
EXTRACT(DAY FROM ( a.END_TIME_UTC - a.START_TIME_UTC) DAY TO SECOND) * 60 * 60 * 24
) AS NUMBER(19,0)) AS DURATION
FROM cycleset cs
INNER JOIN mshist.CYCLEDELAY a ON cs.CYCLE_OID = a.OID)
SELECT MACHINE_NAME, SUM(DURATION) AS EVENT_DURATION, SUM(PAYLOAD) AS PAYLOAD
FROM eventset
GROUP BY
MACHINE_NAME
对于SQL。
SELECT
UPPER(MACH_NAME) AS MACHINE_NAME
, CAST(SUM(f.SPLIT_DURATION) AS NUMERIC(19,0) ) AS DURATION,
SUM(f.EVENT_PAYLOAD) AS PAYLOAD
FROM [mssol2015pdw].[dbo].[F_CYCLE_SHIFT_HR_EVENT_LU] f
INNER JOIN [mssol2015pdw].[dbo].D_MACHINE m ON f.MACHINE_1_DIM_KEY = m.DIMENSION_KEY
INNER JOIN [mssol2015pdw].[dbo].D_CYCLE c ON f.[CYCLE_DIM_KEY] = c.DIMENSION_KEY
WHERE m.DIMENSION_KEY > 0
AND c.CYCLE_OID BETWEEN 1705497113111 AND 1705497596716
GROUP BY UPPER(MACH_NAME)
数据应按机器名称排序,它在oracle中排序,但不在sql中排序。 我试图比较两列中的数据是否相同。 两个查询的数据计数也不相同。
答案 0 :(得分:1)
只需将Order by MACHINE_NAME
添加到您的两个查询的末尾,您也可以在查询结尾处添加Order by 1
,因为MACHINE_NAME
是第一个字段