Question

<markets xmlns="http://www.eoddsmaker.net/schemas/markets/1.0" D="2015-03-23T23:12:34" CNT="1521">
 <S I="50" N="Football">
  <C I="65" N="Russia">
    <L I="167" N="Premier League">
      <E I="1049367" DT="2015-04-05T15:00:00" ISH="0" BKS="20" T1="Ufa" T2="Terek Groznyi" T1I="79698" T2I="44081">
        <M K="1x2">
          <B I="81" BTDT="2015-03-23T23:04:00,825">
            <O N="1" V="3"/>
            <O N="X" V="3.1"/>
            <O N="2" V="2.25"/>
        </B>
      </M>
     </E>
    </L>
   </C>
 </S>
</markets>

我正在尝试使用Python中的etree解析此XML。我以前做过XML解析，但文档一直都是格式化的。

  <tag> value </tag>

我不确定如何将“D”与“市场”以及所有其他值隔离开来。

这是我打开和解析XML Doc的方式：

z = gzip.open("code2.zip", "r")

tree = etree.parse(z)
print(etree.tostring(tree, pretty_print=True))

我试过了：

for markets in tree.findall('markets'):
    print "found"

然而，这不起作用。我会很感激一些提示/建议。希望一旦我获得第一个“D”提取，我将能够得到其余的。

Answer 1

处理具有默认命名空间的XML时，这是一个常见错误。您的XML具有默认名称空间，即没有前缀声明的名称空间，此处为：

的xmlns = “http://www.eoddsmaker.net/schemas/markets/1.0”

因此，在您的情况下，在该命名空间中隐式考虑所有元素。使用xpath()查询命名空间中元素的一种可能方法：

.......
#creating prefix-to-namespace_uri mapping
ns = {'d' : 'http://www.eoddsmaker.net/schemas/markets/1.0'}

#use registered prefix along with the element name to query, and pass the mapping as 2nd argument
markets = tree.xpath('//d:markets', namespaces=ns)[0]

#get and print value of D attribute from <markets> :
print markets.get('D')

Answer 2

我在没有etree知识的情况下回答这个问题。我只是打开以下页面： https://docs.python.org/2/library/xml.etree.elementtree.html#parsing-xml

您正在寻找的是属性，并展示了如何非常清楚地推导出它们：

tree = etree.parse(z)
root = tree.getroot()
print root.attrib

<markets>元素的所有属性，如D和CNT。

你应该能够自己弄清楚其余部分。你只需循环遍历每个元素的子元素并从每个元素中获取.attrib。

考虑到我很容易找到这个答案，请在发布问题之前再做一些研究：）

P.S。这个答案是为Python 2.7编写的。对于Python 3，它将是 print(tree.attrib)

Answer 3

使用xml.etree

尝试此操作

import xml.etree.ElementTree as ET
root = ET.fromstring("""<markets xmlns="http://www.eoddsmaker.net/schemas/markets/1.0" D="2015-03-23T23:12:34" CNT="1521">
     <S I="50" N="Football">
      <C I="65" N="Russia">
        <L I="167" N="Premier League">
          <E I="1049367" DT="2015-04-05T15:00:00" ISH="0" BKS="20" T1="Ufa" T2="Terek Groznyi" T1I="79698" T2I="44081">
            <M K="1x2">
              <B I="81" BTDT="2015-03-23T23:04:00,825">
                <O N="1" V="3"/>
                <O N="X" V="3.1"/>
                <O N="2" V="2.25"/>
            </B>
          </M>
         </E>
        </L>
       </C>
     </S>
    </markets>""")

>>>print root.attrib
{'CNT': '1521', 'D': '2015-03-23T23:12:34'}
>>>print root[0].attrib
{'I': '50', 'N': 'Football'}
#and so on to next parse next line

如果需要从xml文件进行解析。

import xml.etree.ElementTree as ET
tree = ET.parse('file.xml')
root = tree.getroot()

有关详情，请参阅https://docs.python.org/2/library/xml.etree.elementtree.html

Answer 4

print markets.get('D');

打印＆＃39; D＆＃39;市场（根）

for element in tree.iterfind(".//{*}<Tag to search for>"):
   print element.get("<Attribute to look for>");

将迭代当前节点封装的XML文件中的元素，并在iterfind（）中打印每个元素的指定属性。

例如：

for element in tree.iterfind(".//{*}O"):
   print element.get("N");

将打印

1
X
2

另请注意，如果XML文档中有多个名称空间，则必须在传递给iterfind（）的字符串中的花括号中指定以匹配要在其下搜索的名称空间。

for element in tree.iterfind(".//{http://www.eoddsmaker.net/schemas/markets/1.0}<Tag to search for>"):

使用Python LXML从XML读取元素值

4 个答案: