RabbitMQ 3.5现在supports message priority; 但是,我无法建立一个有效的例子。我把我的代码放在下面。它包括我期望的输出和实际的输出。我会对更多文档和/或工作示例感兴趣。
所以我的问题很简单:如何在Rabbit 3.5.0.0中使用消息优先级?
出版商:
using System;
using RabbitMQ.Client;
using System.Text;
using System.Collections.Generic;
class Publisher
{
public static void Main()
{
var factory = new ConnectionFactory() { HostName = "localhost" };
using (var connection = factory.CreateConnection())
{
using (var channel = connection.CreateModel())
{
IDictionary <String , Object> args = new Dictionary<String,Object>() ;
args.Add(" x-max-priority ", 10);
channel.QueueDeclare("task_queue1", true, false, true, args);
for (int i = 1 ; i<=10; i++ )
{
var message = "Message";
var body = Encoding.UTF8.GetBytes(message + " " + i);
var properties = channel.CreateBasicProperties();
properties.SetPersistent(true);
properties.Priority = Convert.ToByte(i);
channel.BasicPublish("", "task_queue1", properties, body);
}
}
}
}
}
消费者:
using System;
using RabbitMQ.Client;
using RabbitMQ.Client.Events;
using System.Text;
using System.Threading;
using System.Collections.Generic;
namespace Consumer
{
class Worker
{
public static void Main()
{
var factory = new ConnectionFactory() { HostName = "localhost" };
using (var connection = factory.CreateConnection())
{
using (var channel = connection.CreateModel())
{
IDictionary<String, Object> args = new Dictionary<String, Object>();
channel.BasicQos(0, 1, false);
var consumer = new QueueingBasicConsumer(channel);
IDictionary<string, object> consumerArgs = new Dictionary<string, object>();
channel.BasicConsume( "task_queue1", false, "", args, consumer);
Console.WriteLine(" [*] Waiting for messages. " +
"To exit press CTRL+C");
while (true)
{
var ea = (BasicDeliverEventArgs)consumer.Queue.Dequeue();
var body = ea.Body;
var message = Encoding.UTF8.GetString(body);
Console.WriteLine(" [x] Received {0}", message);
channel.BasicAck(ea.DeliveryTag, false);
}
}
}
}
}
}
实际输出:
[*] Waiting for messages. To exit press CTRL+C
[x] Received Message 1
[x] Received Message 2
[x] Received Message 3
[x] Received Message 4
[x] Received Message 5
[x] Received Message 6
[x] Received Message 7
[x] Received Message 8
[x] Received Message 9
[x] Received Message 10
预期产出:
[*] Waiting for messages. To exit press CTRL+C
[x] Received Message 10
[x] Received Message 9
[x] Received Message 8
[x] Received Message 7
[x] Received Message 6
[x] Received Message 5
[x] Received Message 4
[x] Received Message 3
[x] Received Message 2
[x] Received Message 1
更新#1。 我在Java here中找到了一个例子。然而,它是Rabbit 3.4.x.x.添加到3.5中的插入。 我能看到的唯一区别是它们将优先级表示为int而我的是一个字节。但我觉得那是一个红鲱鱼。我在这里有点不知所措。
答案 0 :(得分:8)
我解决了。 这是一个愚蠢的错误。 我写道:
args.Add(" x-max-priority ", 10);
应该是
args.Add("x-max-priority", 10);
我会放弃这一点,以便其他人可以在C#中找到Rabbitmq 3.5优先级队列的工作示例。
答案 1 :(得分:2)
Node JS中类似的RabbitMq优先级队列实现
安装amqplib
为了测试,我们需要安装amqplib
npm install amqplib
Publisher(send.js)
#!/usr/bin/env node
var amqp = require('amqplib/callback_api');
function bail(err, conn) {
console.error(err);
if (conn) conn.close(function() { process.exit(1); });
}
function on_connect(err, conn) {
if (err !== null) return bail(err);
// name of queue
var q = 'hello';
var msg = 'Hello World!';
var priorityValue = 0;
function on_channel_open(err, ch) {
if (err !== null) return bail(err, conn);
// maxPriority : max priority value supported by queue
ch.assertQueue(q, {durable: false, maxPriority: 10}, function(err, ok) {
if (err !== null) return bail(err, conn);
for(var index=1; index<=100; index++) {
priorityValue = Math.floor((Math.random() * 10));
msg = 'Hello World!' + ' ' + index + ' ' + priorityValue;
ch.publish('', q, new Buffer(msg), {priority: priorityValue});
console.log(" [x] Sent '%s'", msg);
}
ch.close(function() { conn.close(); });
});
}
conn.createChannel(on_channel_open);
}
amqp.connect(on_connect);
订阅者(receive.js)
#!/usr/bin/env node
var amqp = require('amqplib/callback_api');
function bail(err, conn) {
console.error(err);
if (conn) conn.close(function() { process.exit(1); });
}
function on_connect(err, conn) {
if (err !== null) return bail(err);
process.once('SIGINT', function() { conn.close(); });
var q = 'hello';
function on_channel_open(err, ch) {
ch.assertQueue(q, {durable: false, maxPriority: 10}, function(err, ok) {
if (err !== null) return bail(err, conn);
ch.consume(q, function(msg) { // message callback
console.log(" [x] Received '%s'", msg.content.toString());
}, {noAck: true}, function(_consumeOk) { // consume callback
console.log(' [*] Waiting for messages. To exit press CTRL+C');
});
});
}
conn.createChannel(on_channel_open);
}
amqp.connect(on_connect);
执行命令
node send.js
它将创建一个名为“hello”的队列,并使用默认的AMQP交换将其填充为“1000”样本消息。
node receive.js
它将作为消费者订阅在队列中等待的消息。
答案 2 :(得分:0)
另一种可能性(对于未来的搜索者)
&#34; Push&#34;消息传递方法似乎并不尊重优先权。
http://rabbitmq.docs.pivotal.io/35/rabbit-web-docs/dotnet-api-guide.html.html
下面的是来自上述网址的引用。我把重要的部分加粗了。
按订阅检索邮件(&#34;推送API&#34;)
接收消息的另一种方法是使用IBasicConsumer接口设置订阅。 消息将在到达时自动传递,而不是必须主动请求。实现消费者的一种方法是使用便利类EventingBasicConsumer,它将交付和其他消费者生命周期事件作为C#发送事件:
var consumer = new EventingBasicConsumer(channel);
consumer.Received += (ch, ea) =>
{
var body = ea.Body;
// ... process the message
ch.BasicAck(ea.DeliveryTag, false);
};
String consumerTag = channel.BasicConsume(queueName, false, consumer);
通过更改为&#34; pull&#34;方法,优先权似乎得到尊重。但是,在下面的引用(来自上面的同一个网址),看起来有一个权衡(我加粗)
获取个人消息(&#34;拉动API&#34;) 要检索单个邮件,请使用IModel.BasicGet。返回的值是BasicGetResult的一个实例,可以从中提取标题信息(属性)和消息正文:
bool noAck = false;
BasicGetResult result = channel.BasicGet(queueName, noAck);
if (result == null) {
// No message available at this time.
} else {
IBasicProperties props = result.BasicProperties;
byte[] body = result.Body;
...
由于上面的noAck = false,您还必须调用IModel.BasicAck以确认您已成功接收并处理了该消息:
...
// acknowledge receipt of the message
channel.BasicAck(result.DeliveryTag, false);
}
请注意,使用此API提取邮件的效率相对较低。 如果您更喜欢RabbitMQ将邮件推送到客户端,请参阅下一节的
(在这种情况下,&#34; next&#34;部分将带您进入本文顶部的&#34; push&#34;方法)