Question

我正在开发一个intentservice，它将对服务器执行httpget并检索json字符串。

我正在使用以下代码，该代码在服务器启动时起作用：

 private String getServerContentsJson() throws IOException {
    HttpClient httpclient = new DefaultHttpClient();

   HttpResponse  response = httpclient.execute(new HttpGet(url));


    StatusLine statusline = response.getStatusLine();

    if(statusline.getStatusCode() == HttpStatus.SC_OK){

        ByteArrayOutputStream out = new ByteArrayOutputStream();
        response.getEntity().writeTo(out);
        String responseString = out.toString();
        out.close();
        return responseString;}

    else{
        //Closes the connection.
        response.getEntity().getContent().close();
        throw new IOException(statusline.getReasonPhrase());

    }

问题是当服务器出现故障时，我想正确处理它，但我不清楚如何才能做到这一点。根据文档httpclient.execute将返回正确的响应，或者抛出IOException或ClientProtocolException，但是我得到的HttpHostConnectException: Connection to http://irrelevantURL refused似乎没有追溯到我的代码。该应用程序然后崩溃。有什么建议吗？

这是完整的堆栈跟踪：

W/System.err﹕ org.apache.http.conn.HttpHostConnectException: Connection to http://irrelevantURL refused
W/System.err﹕ at org.apache.http.impl.conn.DefaultClientConnectionOperator.openConnection(DefaultClientConnectionOperator.java:183)
W/System.err﹕ at org.apache.http.impl.conn.AbstractPoolEntry.open(AbstractPoolEntry.java:164)
W/System.err﹕ at org.apache.http.impl.conn.AbstractPooledConnAdapter.open(AbstractPooledConnAdapter.java:119)
W/System.err﹕ at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:360)
W/System.err﹕ at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:555)
W/System.err﹕ at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:487)

编辑：我想这与服务器关闭无关，但由于某种原因拒绝连接，问题仍然存在，但我仍然想要正确处理这个问题，以便应用程序不会崩溃

Answer 1

HttpHostConnectException是一种IOException，您没有正确处理它。你应该有类似下面的东西。如果status_code不是200，您可能不想抛出异常，而是返回有意义的错误responseString

  private String getServerContentsJson()
    throws IOException {
    HttpClient httpclient = new DefaultHttpClient();

    String responseString = null;
    HttpResponse response = null;
    try {
      response = httpclient.execute(new HttpGet(url));

      StatusLine statusline = response.getStatusLine();

      if (statusline.getStatusCode() == HttpStatus.SC_OK) {
        ByteArrayOutputStream out = new ByteArrayOutputStream();
        response.getEntity().writeTo(out);
        responseString = out.toString();
        out.close();
        return responseString;
      } else {
        responseString = statusline.getReasonPhrase();
      }
    } catch (IOException e) {
      throw new IOException(e.getMessage(), e);
      //OR:
      //responseString = "Could not reach server, please try again";
    } finally {
      if (response != null) {
        response.getEntity().consumeContent();
      }
    }
    return responseString;
  }

Apache httpclient android处理连接拒绝

1 个答案: