Question

我有一个XML实例，它有许多我想删除的节点。我知道如何获取这些节点的列表，但我将如何删除它们？之后我将不得不向XMLList添加新项。不确定是否会改变答案。我看到XMLList上有一个replace（）方法。

ActionScript：

var xmllist:XMLList = myXML.Hyperlink;

XML：

<Document>
    <HyperlinkURLDestination Self="HyperlinkURLDestination/http%3a//test.com#1stMultilineLink/" DestinationUniqueKey="1" Name="http://test.com#1stMultilineLink/" DestinationURL="http://test.com#1stMultilineLink/" Hidden="false"/>
    <HyperlinkURLDestination Self="HyperlinkURLDestination/http%3a//test.com#inlinehyperlink_noshareddestination" DestinationUniqueKey="2" Name="http://test.com#inlinehyperlink_noshareddestination" DestinationURL="http://test.com#inlinehyperlink_noshareddestination" Hidden="true"/>
    <HyperlinkURLDestination Self="HyperlinkURLDestination/http%3a//google.com#multilinehyperlink" DestinationUniqueKey="3" Name="http://google.com#multilinehyperlink" DestinationURL="http://google.com#multilinehyperlink" Hidden="false"/>
    <Hyperlink Self="ufc" Name="is a  multiline hyperlink that terminates here" Source="uf9" Visible="false" Highlight="None" Width="Thin" BorderStyle="Solid" Hidden="false" DestinationUniqueKey="1">
        <Properties>
            <BorderColor type="enumeration">Black</BorderColor>
            <Destination type="object">HyperlinkURLDestination/http%3a//test.com#1stMultilineLink/</Destination>
        </Properties>
    </Hyperlink>
    <Hyperlink Self="u112" Name="hyperlink inline" Source="u111" Visible="false" Highlight="None" Width="Thin" BorderStyle="Solid" Hidden="false" DestinationUniqueKey="2">
        <Properties>
            <BorderColor type="enumeration">Black</BorderColor>
            <Destination type="object">HyperlinkURLDestination/http%3a//test.com#inlinehyperlink_noshareddestination</Destination>
        </Properties>
    </Hyperlink>
    <Hyperlink Self="u137" Name="another multline hyperlink" Source="u136" Visible="false" Highlight="Outline" Width="Thick" BorderStyle="Solid" Hidden="false" DestinationUniqueKey="3">
        <Properties>
            <BorderColor type="enumeration">Purple</BorderColor>
            <Destination type="object">HyperlinkURLDestination/http%3a//google.com#multilinehyperlink</Destination>
        </Properties>
    </Hyperlink>
</Document>

Answer 1

行。我找到了一些方法。

方法1.使用XMLListCollection。这似乎从原始XML中删除了项目：

var hyperlinksList:XMLList = myXML.Hyperlink;
var myXMLListCollection:XMLListCollection = new XMLListCollection(hyperlinksList);
myXMLListCollection.removeAll();

方法2.直接从XML中删除节点：

delete myXML.Hyperlink;

然后我可以使用XMLListCollection.addItem（）：

再次添加它们

myXMLListCollection.addItem(<Hyperlink id="mylink"/>);

如何使用E4X删除某种类型的所有节点？

1 个答案: