Question

我有一些ubuntu和centos的剧本，我想用main.yml来检查“何时：ansible_os_family =='RedHat'或ansible_distribution =='Centos'”运行剧本（有些人很多:-)）< / p>

如果我只是

-include: centos-xxx.yml
-include: centos-xaa.yml
-include: centos-xsss.yml

它将运行所有这些我希望如果满足条件，剧本将会运行

我没有找到任何说明如何运行的文档包含：如果可能的话，我会尝试不为每个包含任务创建一个

感谢您的帮助

Answer 1

您可以使用when conditional包含文件。事实上，这有点普遍。

- include: centos-xxx.yml
  when: ansible_os_family == 'RedHat' or ansible_distribution == 'Centos'
- include: debian-xxx.yml
  when: ansible_distribution == 'Debian'

根据您的评论 - 如果您想按顺序运行它们，您有两种选择。这是直截了当的：

- include: centos-a.yml
  when: ansible_os_family == 'RedHat' or ansible_distribution == 'Centos'
- include: centos-b.yml
  when: ansible_os_family == 'RedHat' or ansible_distribution == 'Centos'
- include: centos-c.yml
  when: ansible_os_family == 'RedHat' or ansible_distribution == 'Centos'
- include: centos-d.yml
  when: ansible_os_family == 'RedHat' or ansible_distribution == 'Centos'

或者，你可以这样做：

- include: centos.yml
  when: ansible_os_family == 'RedHat' or ansible_distribution == 'Centos'

和centos.yml内部：

- include: centos-a.yml
- include: centos-b.yml
- include: centos-c.yml
- include: centos-d.yml

ansible - 如果condition为true，则运行一些包含yml文件

1 个答案: