我想将以下查询作为单个查询。
我的意图是获得job_status = A
,其中job_status = A
和总数的计数。
select
WORKSTATION_NAME AS CPU,
count(*) AS TOTAL
from
MDL.JOB_HISTORY_V
where
MONTH(JOB_RUN_DATE_TIME) = 01
AND YEAR(JOB_RUN_DATE_TIME) = 2015
GROUP BY
WORKSTATION_NAME
select
WORKSTATION_NAME AS CPU,
count(*) AS SUCCESS_RUNS
from
MDL.JOB_HISTORY_V
where
JOB_STATUS = 'S'
and MONTH(JOB_RUN_DATE_TIME) = 01
AND YEAR(JOB_RUN_DATE_TIME) = 2015
GROUP BY
WORKSTATION_NAME
select
WORKSTATION_NAME AS CPU,
count(*) AS ABEND_RUNS
from
MDL.JOB_HISTORY_V
where
JOB_STATUS = 'A'
and MONTH(JOB_RUN_DATE_TIME) = 01
AND YEAR(JOB_RUN_DATE_TIME) = 2015
GROUP BY
WORKSTATION_NAME
答案 0 :(得分:0)
您可以使用以下条件计算:
select WORKSTATION_NAME AS CPU
, count(*) AS TOTAL
, count(case when JOB_STATUS = 'S' then 1 end) as SUCCESS_RUNS
, count(case when JOB_STATUS = 'A' then 1 end) as ABEND_RUNS
from MDL.JOB_HISTORY_V
where MONTH(JOB_RUN_DATE_TIME) = 01
AND YEAR(JOB_RUN_DATE_TIME) = 2015
GROUP BY WORKSTATION_NAME