Question

我已经看到很多问题如何排序1,10,2,3等。

我在表单中导入了一些Json数据：@"arrived"，@"boarding"，@"1"，@"2"，@"3"等。

我目前只有一个不区分大小写的排序：

sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"time" ascending:YES selector:@selector(caseInsensitiveCompare:)];

首先对这些数字进行排序，然后按照上面显示的形式对单词进行排序。

我有什么选择呢？感谢

Answer 1

这个冗长的比较器可以解决这个问题：

NSArray *testArray = @[@"3", @"boarding", @"2", @"arrived", @"1"];

NSArray *sortedArray = [testArray sortedArrayUsingComparator:^NSComparisonResult(NSString *obj1, NSString *obj2) {
    NSInteger firstInteger = 0;
    BOOL isInteger1 = [[NSScanner scannerWithString:obj1] scanInteger:&firstInteger];

    NSInteger secondInteger = 0;
    BOOL isInteger2 = [[NSScanner scannerWithString:obj2] scanInteger:&secondInteger];

    if (isInteger1 && isInteger2) {
        // Normal integer comparison
        if (firstInteger > secondInteger) {
            return NSOrderedDescending;
        }
        else if (secondInteger > firstInteger) {
            return NSOrderedAscending;
        }
        else {
            return NSOrderedSame;
        }
    }
    else if (isInteger1) {
        return NSOrderedDescending;
    }
    else if (isInteger2) {
        return NSOrderedAscending;
    }
    else {
        return [obj1 compare:obj2 options:NSCaseInsensitiveSearch];
    }
}];

修改

示例输出：

Printing description of sortedArray: <__NSArrayI 0x7ffacaa26da0>( arrived, boarding, 1, 2, 3

Answer 2

尝试这个

    NSComparator compare=^(id obj1, id obj2) {
    NSString *s1 = [obj1 substringToIndex:1];
    NSString *s2 = [obj2 substringToIndex:1];

    NSRange r1 = [s1 rangeOfCharacterFromSet:[NSCharacterSet decimalDigitCharacterSet]];
    NSRange r2 = [s2 rangeOfCharacterFromSet:[NSCharacterSet decimalDigitCharacterSet]];
    if (r1.location == r2.location ) { // either both start with a number or both with a letter
        return [obj1 compare:obj2 options:NSDiacriticInsensitiveSearch|NSCaseInsensitiveSearch];
    } else {  // one starts wit a letter, the other with a number
        if ([s1 rangeOfCharacterFromSet:[NSCharacterSet decimalDigitCharacterSet]].location == NSNotFound) {
            return NSOrderedAscending;
        }
        return NSOrderedDescending;
    }
};

NSSortDescriptor *desc=[[NSSortDescriptor alloc]initWithKey:@"time" ascending:YES comparator:compare];

originalArray =  [originalArray sortedArrayUsingDescriptors:@[desc]];

可以帮到你。

iOS - SortDescriptor，其中内容是字母和数字

2 个答案: