朋友您好我有3张如下表:
property_master -->p_id, p_name,r_id
transction_master -->t_id,p_id,amount,user_cat_id,r_id
user_trans_cat-->user_cat_id,cat_name,trans_id ,r_id
我的查询如下
SELECT property_master.p_id AS "Product Code",
property_master.p_name AS "Description",
(SELECT SUM(amount)
FROM transction_master ,property_master
JOIN user_trans_cat ON transction_master.user_cat_id = user_trans_cat.user_cat_id
WHERE user_trans_cat.trans_id =1 and transction_master.date between '2015-01-01' and '2015-12-31'
group by property_master.p_id
) AS "Income",
(SELECT SUM(amount)
FROM transction_master ,property_master
JOIN user_trans_cat ON transction_master.user_cat_id = user_trans_cat.user_cat_id
WHERE user_trans_cat.trans_id =2 and transction_master.date between '2015-01-01' and '2015-12-31'
group by property_master.p_id
) AS "Expense"
FROM property_master ,transction_master where property_master.r_id = 1
Group by property_master.p_id
交易表
输出 我希望总收入,费用价值按照原则明智但是当我在查询之上运行它会给我所有财产的总收入价值任何想法我怎么能解决它?
答案 0 :(得分:1)
下面怎么样 -
select
pm.p_id AS "Product Code",
pm.p_name AS "Description",
sum( case when utrc.trans_id =1 then tm.amount else 0 end ) as "Income",
sum( case when utrc.trans_id =2 then tm.amount else 0 end ) as "Expense"
from transction_master tm
join property_master pm on pm.p_id = tm.p_id
join user_trans_cat utrc on utrc.user_cat_id = tm.user_cat_id
where
tm.date between '2015-01-01' and '2015-12-31'
group by
pm.p_id
更新:如果您需要列出所有属性,即使它们是 不在事务主数据中,那么您需要更改要选择的查询 从property_master然后左连接
from property_master pm
left join transction_master tm on pm.p_id = tm.p_id
left join user_trans_cat utrc on utrc.user_cat_id = tm.user_cat_id
现在左边连接条件只是内部连接,所以where条件需要作为连接条件移动,以便查询变为
select
pm.p_id AS "Product Code",
pm.p_name AS "Description",
sum( case when utrc.trans_id =1 then tm.amount else 0 end ) as "Income",
sum( case when utrc.trans_id =2 then tm.amount else 0 end ) as "Expense"
from property_master pm
left join transction_master tm on pm.p_id = tm.p_id
and tm.date between '2015-01-01' and '2015-12-31'
left join user_trans_cat utrc on utrc.user_cat_id = tm.user_cat_id
group by
pm.p_id
答案 1 :(得分:0)
你可以尝试这个伴侣:
SELECT
pm.p_id 'Product Code',
pm.p_name 'Description',
SUM(CASE WHEN utc.r_id = 1 THEN tm.amount ELSE 0 END) 'Income',
SUM(CASE WHEN utc.r_id = 2 THEN tm.amount ELSE 0 END) 'Expense'
FROM
transction_master tm
JOIN property_master pm ON tm.p_id = pm.p_id
JOIN user_trans_cat utc ON utc.trans_id = tm.t_id
WHERE
tm.date BETWEEN '2015-12-31' AND '2015-01-01'
GROUP BY
pm.p_id;