Question

在我的表中，我正在存储供应商的购买账单。像：

| Bill No | Vendor | Item | Bill Amount |
| 1929    | abc    | 123  |   840.00    | <-- Treat these as one
| 1929    | abc    | 234  |   840.00    | <-- Treat these as one
| 23874   | xyz    | peo  |  1024.00    |
| 1942    | abc    | pop  |   600.00    |
| 4720    | mno    | test |  1250.00    |

我想获得供应商的总金额组，其中mysql将相同的账单号码视为1条记录。输出应该是。

| Vendor | Total Amount |
| abc    |    1440.00   | <-- It should be 1440 instead of 2280
| xyz    |    1024.00   |
| mno    |    1250.00   |

Answer 1

一种方法是在派生表中获取不同的帐单编号及其值，然后对这些值使用sum并进行分组。

考虑下表

mysql> select * from bills ;
+--------+--------+------+-------------+
| billno | vendor | item | bill_amount |
+--------+--------+------+-------------+
|   1929 | abc    | 123  |      840.00 |
|   1929 | abc    | 234  |      840.00 |
|  23874 | xyz    | peo  |     1024.00 |
|   1942 | abc    | pop  |      600.00 |
|   4720 | mno    | test |     1250.00 |
+--------+--------+------+-------------+
5 rows in set (0.00 sec)

然后通过以下查询我们可以得到数据

select 
sum(x.bill_amount) as total_amount,
x.vendor from (
   select distinct billno, vendor , bill_amount from bills 
)x 
group by x.vendor ;


+--------------+--------+
| total_amount | vendor |
+--------------+--------+
|      1440.00 | abc    |
|      1250.00 | mno    |
|      1024.00 | xyz    |
+--------------+--------+
3 rows in set (0.00 sec)

Answer 2

尝试使用SUM（）聚合：

SELECT 
      Vendor,
      SUM([Bill Amount]) AS [Total Amount]
FROM YourTableName
GROUP BY [Bill No],Vendor

表中的帐单金额总和，并使用相同的帐单处理重复行

2 个答案: