我有一个mdx查询,它可以为我提供明确的开斋节,地区和国家/地区:
SELECT ([Measures].[Active Tiles Count]) ON 0,
NON EMPTY ([Employee].[Employee Id].Children,[Employee - Business Region]. [Region Code].Children,[Employee - Country].[Country Code].Children) ON 1
FROM [OLAP Pre]
WHERE (
{[Employee Statuses].[Status Id].&[1],[Employee Statuses].[Status Id].&[4],[Employee Statuses].[Status Id].&[3]},
{[Business Region].[Abbreviation].&[APJ],[Business Region].[Abbreviation].&[EMEA],[Business Region].[Abbreviation].&[Americas]},
{[Employee Types].[Bits].&[1],[Employee Types].[Bits].&[9],
[Employee Types].[Bits].&[25],[Employee Types].[Bits].&[5],
[Employee Types].[Bits].&[13],[Employee Types].[Bits].&[29]}
,{[Date].[Date].&[2015-03-18T00:00:00]:NULL})
但我希望 COUNT ( DISTINCT (employEEid))按地区和国家/地区分组。
怎么做?
答案 0 :(得分:1)
创建DISTINCT COUNT MEASURE,它是预定义的聚合类型
答案 1 :(得分:0)
尝试使用DISTINCTCOUNT
功能
WITH MEMBER Measures.[CountOfDistinctEmployes] AS
DISTINCTCOUNT([Employee].[Employee Id].Children)
SELECT {[Measures].[Active Tiles Count], Measures.[CountOfDistinctEmployes]} ON 0,
NON EMPTY ([Employee].[Employee Id].Children,[Employee - Business Region]. [Region Code].Children,[Employee - Country].[Country Code].Children) ON 1
FROM [OLAP Pre]
WHERE (
{[Employee Statuses].[Status Id].&[1],[Employee Statuses].[Status Id].&[4],[Employee Statuses].[Status Id].&[3]},
{[Business Region].[Abbreviation].&[APJ],[Business Region].[Abbreviation].&[EMEA],[Business Region].[Abbreviation].&[Americas]},
{[Employee Types].[Bits].&[1],[Employee Types].[Bits].&[9],
[Employee Types].[Bits].&[25],[Employee Types].[Bits].&[5],
[Employee Types].[Bits].&[13],[Employee Types].[Bits].&[29]}
,{[Date].[Date].&[2015-03-18T00:00:00]:NULL})