我试图像xmlhttp对象那样调用webmethod
var v2 = JSON.stringify({ province: 'Ontario' });
xmlhttp.open("POST", "http://localhost:49771/rentalone/lp.aspx/getCities?" + v2, true);
问题是当我使用“?”时像这样
/getCities?" + v2
它为我提供了错误代码500“缺少参数”
的值但是当我使用“/”
时 /getCities/" + v2
它给我错误代码http 400.床位要求
如何调用具有输入参数的webmethod?
答案 0 :(得分:0)
也许改变它以便v2='province=ontario';
?
好的......那不行,所以也许尝试这样的事情(从评论中的链接修改): var v2 = JSON.stringify({province:'Ontario'}); var http = new XMLHttpRequest();
http.open("POST", "http://localhost:49771/rentalone/lp.aspx/getCities", true);
//Send the proper header information along with the request
http.setRequestHeader("Content-type", "application/json");
http.setRequestHeader("Content-length", v2.length);
http.onreadystatechange = function() {//Call a function when the state changes.
if(http.readyState == 4 && http.status == 200) {
alert(http.responseText);
}
}
http.send(v2);