当我点击项目来显示细节时，它会出错

Question

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        at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:183)
        at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:456)
        at java.net.Socket.connect(Socket.java:882)
        at org.apache.http.conn.scheme.PlainSocketFactory.connectSocket(PlainSocketFactory.java:119)
        at org.apache.http.impl.conn.DefaultClientConnectionOperator.openConnection(DefaultClientConnectionOperator.java:144)
        at org.apache.http.impl.conn.AbstractPoolEntry.open(AbstractPoolEntry.java:164)
        at org.apache.http.impl.conn.AbstractPooledConnAdapter.open(AbstractPooledConnAdapter.java:119)
        at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:360)
        at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:555)
        at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:487)
        at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:465)
        at com.example.talkless.navlayout.JSON.JSONParser.makeHttpRequest(JSONParser.java:62)
        at com.example.talkless.navlayout.Activity.EditInventory$GetProductDetails$1.run(EditInventory.java:133)
 o

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我创建了listview，但是如果我点击项目以显示详细信息则会出错。这是我的代码

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                        // getting product details by making HTTP request
                        // Note that product details url will use GET request
                        JSONObject json = jsonParser.makeHttpRequest(
                                url_item_detials, "GET", params);

                           

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请告诉我