Question

#import <UIKit/UIKit.h>

@interface UIView (Shape)

- (void)setShape:(CGPathRef)shape;

@end

#import "UIView+Shape.h"

@implementation UIView (Shape)
- (void)setShape:(CGPathRef)shape
{
    if (shape == nil) {
        self.layer.mask = nil;
    }

    CAShapeLayer* shapeLayer = [CAShapeLayer layer];
    shapeLayer.path = shape;
    shapeLayer.fillColor = [[UIColor whiteColor] CGColor];
    shapeLayer.strokeColor = [[UIColor redColor] CGColor];
    shapeLayer.lineWidth = 0.5;
    self.layer.mask = shapeLayer;

}
@end

这是我的代码。我想将形状的边框颜色设置为红色，但边框始终是清晰的颜色。我不得不添加一个子图层，代码显示如下。它有效，为什么？

 - (void)setShape:(CGPathRef)shape strokeColor:(UIColor *)color
 {
    if (shape == nil) {
        self.layer.mask = nil;
    }

    CAShapeLayer* shapeLayer = [CAShapeLayer layer];
    shapeLayer.path = shape;
//    shapeLayer.fillColor = [[UIColor whiteColor] CGColor];
//    shapeLayer.strokeColor = [[UIColor redColor] CGColor];
//    shapeLayer.lineWidth = 0.5;
    self.layer.mask = shapeLayer;

    CAShapeLayer *borderLayer = [CAShapeLayer layer];
    borderLayer.path = shape;
    borderLayer.lineWidth = 2;
    borderLayer.fillColor = [[UIColor clearColor] CGColor];
    borderLayer.strokeColor = [color CGColor];
    [self.layer addSublayer:borderLayer];
}

抱歉我的英语很差。

Answer 1

您正在将形状图层添加为遮罩层。这允许掩模层的像素的亮度确定其掩蔽的层的不透明度。听起来这不是你想要的。

而是将您的形状图层添加为视图图层的子图层。改变

self.layer.mask = shapeLayer;

到

[self.layer addSublayer: shapeLayer];

这将使您的形状图层在视图的图层上绘制。

CAShapeLayer的strokeColor不起作用

1 个答案: