Question

我正在尝试将搜索栏添加到ListView。当我点击搜索结果显示正常但当我点击结果的第二页时，我得到了整个结果。

class LegsIndex(FormMixin, generic.ListView):
  form_class = MyForm
  model = Legs
  paginate_by = 5
  template_name = "legs/legshome.html"

def get_queryset(self):
    return self.model.objects.published()

def get_context_data(self, **kwargs):
    context = super(LegsIndex, self).get_context_data(**kwargs)
    return context

def get(self, request, *args, **kwargs):
    form_class = self.get_form_class()
    self.form = self.get_form(form_class)

    search = request.GET.get('search', None)

    if search:
        self.object_list = self.get_queryset().filter(title__icontains=search)
    else:
        self.object_list = self.get_queryset()

    context = self.get_context_data(object_list=self.object_list, form=self.form)
    return self.render_to_response(context)

这样做的正确方法是什么。我需要在表格中设置过滤这些字段，否则显示所有数据。

class MyFilterForm(Form):

search = forms.CharField(widget=forms.TextInput(attrs={'placeholder': 'Looking For ...'}), required=False)
counties = forms.ModelMultipleChoiceField(queryset=Legs.objects.values_list('country', flat=True).distinct(),
                                          widget=forms.CheckboxSelectMultiple(), required=False)
cities = forms.ModelMultipleChoiceField(queryset=Legs.objects.values_list('city', flat=True).distinct(),
                                        widget=forms.CheckboxSelectMultiple(), required=False)

class Meta:
    fields = '__all__'

Answer 1

问题的评论部分：

您可以简单地将请求从视图传递到表单并将其更新为：

#View
class LegsIndex(FormMixin, generic.ListView):
     ....
     def get_form_kwargs(self):
        kwargs = super().get_form_kwargs()
        kwargs.update(request_data=self.request)
        return kwargs


#Form
class MyFilterForm(Form):
    #form fields 

     def __init__(self, *args, request_data=None, **kwargs):
        super().__init__(*args, **kwargs)
        self.fields['search'].initial = request_data.GET.get('search', '')

Answer 2

我构建了一个解决这个问题的库，ListView是可搜索和可分页的，它不会丢失查询参数

https://github.com/SchroterQuentin/django-search-listview

使用ListView的Django搜索栏

2 个答案: