Question

我是初学者所以请......温柔。

以下是代码：

for (i = 0; i<importedData.data.length; i++){
    var b=importedData.data[i].maker;
    console.log(b);
    // console.log(importedData.data[i].maker);

        var bt = importedData.data[i].body;
    console.log(bt);
        var ic = importedData.data[i].inkcolor;
    console.log(ic);
        var pt = importedData.data[i].type;
    console.log(pt);

};

我得到他的结果但是因为有25个不同的对象具有相同的字段，所以有重复。

下面的

是您查看的JSON

exports.data = [
    {
        "type": "ballpoint",
        "maker": "Bic",
        "inkcolor": "blue",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image01.jpg"
    },

    {
        "type": "fountain",
        "maker": "inkwell",
        "inkcolor": "blue",
        "body": "metal",
        "length": "6 inches",
        "img" : "image02.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "Bic",
        "inkcolor": "blue",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image03.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "inkwell",
        "inkcolor": "blue",
        "body": "ceramic",
        "length": "5 inches",
        "img" : "image04.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "luxor",
        "inkcolor": "blue",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image05.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "Bic",
        "inkcolor": "blue",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image06.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "Bic",
        "inkcolor": "blue",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image07.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "montblanc",
        "inkcolor" : "blue",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image08.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "luxor",
        "inkcolor": "blue",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image09.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "Bic",
        "inkcolor": "blue",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image10.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "inkwell",
        "inkcolor": "blue",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image11.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "papermate",
        "inkcolor": "blue",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image12.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "montblanc",
        "inkcolor": "blue",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image13.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "Bic",
        "inkcolor": "blue",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image14.jpg"
    },
    {
        "type": "fountain",
        "maker": "montblanc",
        "inkcolor": "black",
        "body": "gold",
        "length": "6 inches",
        "img" : "image15.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "Bic",
        "inkcolor": "yellow",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image16.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "sharpie",
        "inkcolor": "blue",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image17.jpg"
    },
    {
        "type": "fountain",
        "maker": "papermate",
        "inkcolor": "black",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image18.jpg"
    },
    {
        "type": "felt",
        "maker": "Bic",
        "inkcolor": "blue",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image19.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "technicalpen",
        "inkcolor": "blue",
        "body": "plastic",
        "length": "4 inches",
        "img" : "image20.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "Bic",
        "inkcolor": "red",
        "body": "metal",
        "length": "5 inches",
        "img" : "image21.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "technicalpen",
        "inkcolor": "blue",
        "body": "plastic",
        "length": "5 inches",
        "img" : "image22.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "Bic",
        "inkcolor": "green",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image23.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "parker",
        "inkcolor": "black",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image24.jpg"
    },
    {
        "type": "ballpoint",
        "maker": "uniball",
        "inkcolor": "red",
        "body": "plastic",
        "length": "6 inches",
        "img" : "image25.jpg"
    },
];

Answer 1

通常，您希望对数组进行排序，然后如果存在重复项，则它们将在数组中彼此相邻。

此问题之前已经得到了回答 Removing duplicates in array of objects

或者不是自己编写，而是可以利用现有的实现，例如lodash＆＃39; s https://lodash.com/docs#uniq

Answer 2

如果我理解你在问题评论中的澄清，那么这应该是单独的字段值数组：

var makers = {},
    bodies = {},
    inkcolors = {},
    types = {};

for (var i = 0; i < importedData.data.length; i++) {
    var item = importedData.data[i];
    makers[item.maker] = true;
    bodies[item.body] = true;
    inkcolors[item.inkcolor] = true;
    types[item.type] = true;
};
makers = Object.keys(makers);
bodies = Object.keys(bodies);
inkcolors = Object.keys(inkcolors);
types = Object.keys(types);

console.log(makers);
console.log(bodies);
console.log(inkcolors);
console.log(types);

说明：对象makers，bodies等用作哈希表。首次遇到"Bic"制作者时，makers会获得一个新属性：{ "Bic": true }。在"inkwell"，我们会插入另一个：{ "Bic": true, "inkwell": true }。当我们再次看到"inkwell"时，我们只需将现有属性重新分配给true，因此对象不会更改。这个价值实际上根本不重要;我喜欢true（基本上说“我看到了Bic！我也看到了墨水池！”），但它本身可能是17.5，或者你可以一直保持运行（“我看到了两个Bics！我看到一个墨水瓶！“{ "Bic": 2, "inkwell": 1 }）。这取决于对象中的所有键都是唯一的。最后，我们只是从每个对象中提取这些键作为数组：["Bic", "inkwell", ...]。

我想循环遍历一系列对象，我不想要任何重复

2 个答案: