每次我尝试提交此联系表单时,都会收到以下错误消息:
'请输入您的信息。'
除非我将其留空,否则不会显示名称错误消息和电子邮件错误消息。我试图在HTML中指定帖子。
这是HTML:
<div class="col-md-8 animated fadeInLeft notransition">
<h1 class="smalltitle">
<span>Get in Touch</span>
</h1>
<form action="contact.php" method="post" name="MYFORM" id="MYFORM">
<input name="name" size="30" type="text" id="name" class="col-md-6 leftradius" placeholder="Your Name">
<input name="email" size="30" type="text" id="email" class="col-md-6 rightradius" placeholder="E-mail Address">
<textarea id="message" name="message" class="col-md-12 allradius" placeholder="Message" rows="9"></textarea>
<img src="contact/refresh.jpg" width="25" alt="" id="refresh"/><img src="contact/get_captcha.php" alt="" id="captcha"/>
<br/><input name="code" type="text" id="code" placeholder="Enter Captcha" class="top10">
<br/>
<input value="Send" type="submit" id="Send" class="btn btn-default btn-md">
</form>
</div>
这是PHP:
<?php
//Retrieve form data.
//GET - user submitted data using AJAX
//POST - in case user does not support javascript, we'll use POST instead
$name = ($_GET['name']) ? $_GET['name'] : $_POST['name'];
$email = ($_GET['email']) ?$_GET['email'] : $_POST['email'];
$comment = ($_GET['comment']) ?$_GET['comment'] : $_POST['comment'];
//flag to indicate which method it uses. If POST set it to 1
if ($_POST) $post=1;
//Simple server side validation for POST data, of course, you should validate the email
if (!$name) $errors[count($errors)] = 'Please enter your name.';
if (!$email) $errors[count($errors)] = 'Please enter your email.';
if (!$comment) $errors[count($errors)] = 'Please enter your message.';
//if the errors array is empty, send the mail
if (!$errors) {
//recipient - replace your email here
$to = 'faasdfsdfs@gmail.com';
//sender - from the form
$from = $name . ' <' . $email . '>';
//subject and the html message
$subject = 'Message from ' . $name;
$message = 'Name: ' . $name . '<br/><br/>
Email: ' . $email . '<br/><br/>
Message: ' . nl2br($comment) . '<br/>';
//send the mail
$result = sendmail($to, $subject, $message, $from);
//if POST was used, display the message straight away
if ($_POST) {
if ($result) echo 'Thank you! We have received your message.';
else echo 'Sorry, unexpected error. Please try again later';
//else if GET was used, return the boolean value so that
//ajax script can react accordingly
//1 means success, 0 means failed
} else {
echo $result;
}
//if the errors array has values
} else {
//display the errors message
for ($i=0; $i<count($errors); $i++) echo $errors[$i] . '<br/>';
echo '<a href="index.html">Back</a>';
exit;
}
//Simple mail function with HTML header
function sendmail($to, $subject, $message, $from) {
$headers = "MIME-Version: 1.0" . "\r\n";
$headers .= "Content-type:text/html;charset=iso-8859-1" . "\r\n";
$headers .= 'From: ' . $from . "\r\n";
$result = mail($to,$subject,$message,$headers);
if ($result) return 1;
else return 0;
}
答案 0 :(得分:2)
在您的HTML表单中,您可以为<input...
字段命名&#34;消息&#34;但是当你使用PHP时,你会尝试从$ _GET [&#39; comment&#39;]中获取值。
我认为如果你把这些排成一行,我认为它会解决你的问题。
答案 1 :(得分:0)
我可以看到2个问题:
我建议使用它来检查是否已发送POST
if ( $_SERVER['REQUEST_METHOD'] == 'POST' ) {}
或者如果您要检查的内容不为空
if ( !empty($_POST) ) {}