Question

我想简化以下GNU制作规则：

lib/dir1/org/eclipse/jetty/jetty-http/9.3.0.M2/jetty-http-9.3.0.M2.jar:
        mkdir -p $(dir $@) && curl -o $@ "http://central.maven.org/maven2/org/eclipse/jetty/jetty-http/9.3.0.M2/jetty-http-9.3.0.M2.jar"

lib/dir1/org/eclipse/jetty/jetty-util/9.3.0.M2/jetty-util-9.3.0.M2.jar:
        mkdir -p $(dir $@) && curl -o $@ "http://central.maven.org/maven2/org/eclipse/jetty/jetty-util/9.3.0.M2/jetty-util-9.3.0.M2.jar"

lib/dir1/javax/servlet/javax.servlet-api/3.1.0/javax.servlet-api-3.1.0.jar:
        mkdir -p $(dir $@) && curl -o $@ "http://central.maven.org/maven2/javax/servlet/javax.servlet-api/3.1.0/javax.servlet-api-3.1.0.jar"

lib/dir1/org/slf4j/slf4j-api/1.7.10/slf4j-api-1.7.10.jar:
        mkdir -p $(dir $@) && curl -o $@ "http://central.maven.org/maven2/org/slf4j/slf4j-api/1.7.10/slf4j-api-1.7.10.jar"

如何删除前缀＆＃39; lib / dir1＆＃39;在curl URL中获取一个简单的规则，如：

$(addsuffix lib/dir1/,org/eclipse/jetty/jetty-http/9.3.0.M2/jetty-http-9.3.0.M2.jar org/eclipse/jetty/jetty-util/9.3.0.M2/jetty-util-9.3.0.M2.jar javax/servlet/javax.servlet-api/3.1.0/javax.servlet-api-3.1.0.jar  org/slf4j/slf4j-api/1.7.10/slf4j-api-1.7.10.jar):
    mkdir -p $(dir $@) && curl -o $@ \
     "http://central.maven.org/maven2/$(something $@)"

类似于＆＃39; substring-after＆＃39; ...

Answer 1

$(patsubst lib/dir1/%,%,$@)不起作用吗？

GNU-make：删除第一个目录

1 个答案: