var cars = ["nano", "bmw"];
var bikes = ["pulsar", "splander"];
var con = [];
var foundCars = [];
var foundBikes = [];
var notFoundTransport =[];
for(var i = 0; i<cars.length; i++){
con = prompt("enter your tranport name");
if(con[i] == cars[i]){
foundCars.push(con[i]);
}
}
for(var i = 0; i<2; i++){
alert(foundCars[i]);
}
为什么在警告foundcars数组后它显示未定义的值 例如,nano bmw 它是警报,未定义,未定义 请让我知道我错在哪里。
答案 0 :(得分:0)
首先,您需要将提示的结果添加到con数组中的适当位置。
然后你应该考虑到foundCars的长度迭代数组,而不是硬编码2。
var cars = ["nano", "bmw"];
var bikes = ["pulsar", "splander"];
var con = [];
var foundCars = [];
var foundBikes = [];
var notFoundTransport =[];
for(var i = 0; i<cars.length; i++){
con[i] = prompt("enter your tranport name");
if(con[i] == cars[i]){
foundCars.push(con[i]);
}
}
for(var i = 0; i<foundCars.length; i++){
alert(foundCars[i]);
}
答案 1 :(得分:0)
因为foundCars
永远为空
你应该像这样使用已发现的汽车。
for(var i = 0; i<cars.length; i++){
con = prompt("enter your tranport name");
for(var p = 0; p<cars.length; p++){
if(con == cars[p]){
foundCars.push(con);
}
}
}
并使用for(var i = 0; i<foundCars.length; i++)
for(var i = 0; i<2; i++)
内容
答案 2 :(得分:-1)
请检查:
var cars = ["nano", "bmw"];
var bikes = ["pulsar","splander"];
var con = [];
var foundCars = [];
var foundBikes = [];
var notFoundTransport =[];
var found = false;
var checkExist = false;
for(var i = 0; i<2; i++){
con[i] = prompt("enter your tranport name");
}
for(var i = 0; i<con.length; i++){
for(var j = 0; j<con.length; j++){
if(con[i] == cars[j]){
foundCars.push(con[i]);
found = true;
checkExist = true;
}else if(con[i] == bikes[j]){
foundBikes.push(con[i]);
found = true;
checkExist = true;
}else if(con[i]!=cars[j]&&con[i]!=bikes[j]&&found==false&&j!=0){
notFoundTransport.push(con[i]);
found = true;
}
}
found = false;
}
console.log(foundCars);
console.log(foundBikes);
console.log(notFoundTransport);