Question

在这个问题上苦苦挣扎..我的SQL查询在PHP myAdmin中运行，但不在页面上..

网址： http://www.copleycaravanservices.co.uk/Caravans.php?room_id=1&foreign_id=1 还有另一个查询适用于url的room_id部分

不起作用的代码：

<?php
require_once('db_config.php');
mysql_select_db($dbname, $db);
$sql1 = "SELECT * FROM  `SS_hotel_booking_multi_lang` 
WHERE  `foreign_id` = " . $_GET['foreign_id'] . "
AND  `locale` = '1'
AND  `field` =  'description'
AND  `source` =  'data'";
$result1 = mysql_query($sql1, $db) or die(mysql_error());
$CaravanDesc = mysql_fetch_assoc($result1);
?>

数据库:(希望这显示正确！）

id  foreign_id  model   locale  field   content              source
7365    1       pjRoom    1     name    Promenade 654          data
7366    1       pjRoom    1  description This caravan sleeps 6 data
7371    2       pjRoom    1     name    Butlins Sandhills 14   data
7372    2       pjRoom    1  description 4 Day Passes included data

Answer 1

我认为这应该通过删除列名

的引号来完成

 <?php
    require_once('db_config.php');
    mysql_select_db($dbname, $db);
    $sql1 = "SELECT * FROM  `SS_hotel_booking_multi_lang` 
    WHERE  foreign_id = " . $_GET['foreign_id'] . "
    AND  locale = '1'
    AND  field =  'description'
    AND  source =  'data'";
    $result1 = mysql_query($sql1, $db) or die(mysql_error());
    $CaravanDesc = mysql_fetch_assoc($result1);
    ?>

WHERE子句中的多个查询

1 个答案: