Question

我只知道sql的基础知识。我有一个过程，我们正在寻找基于某些条件从表中获取行。之前的假设是我们在结果中总是至少有一行。

但现在我们也有可能没有行。我需要更新过程来处理此异常并返回null值作为过程的输出。很感谢任何形式的帮助。

这是程序：

create or replace
PROCEDURE C1_OSO_PC_LIST (v_service_order_id  VARCHAR2,
          C1_OSO_PC_LIST_cv IN OUT cv_types.customer_tp) IS

d_count                 NUMBER := 1;
d_periodic01            VARCHAR2(240) := NULL;
d_apply_day             NUMBER(6);
d_rc_term_id            NUMBER(10);
d_offer_id            NUMBER(10);


CURSOR c_pc_to_add_list IS

  SELECT ofv.offer_id,
    ofv.display_value,
    oi.member_inst_id component_inst_id,
    oi.member_inst_id2 component_inst_id_serv, 
    b.component_id component_id   ---- tymczasowe obejÅ›cie problemu
  FROM ord_item oi,
    EXTERNAL_ENTITY_MAPPING eem,
    EXTERNAL_ENTITY_MAPPING_TYPE eemt,
    C1_OFFER_VALUES ofv,
    P4_BUNDLES b
  WHERE eem.internal_id1          = oi.member_id 
    AND eem.entity_mapping_type   = eemt.entity_mapping_type
    AND eemt.internal_entity_type = 'Component'
    AND eemt.external_entity_type = 'SubSupplementaryOffer'
    AND oi.item_action_id         = 10 -- ADD
    AND oi.member_type            = 40 -- package component
    AND ofv.language_code        = 1
    AND ofv.offer_id              = eem.external_id1
    AND nvl(b.c1_mode, 0) not in (1,2)
    -- AND nvl(b.c1_mode, 0)         = 0
    AND EXISTS (SELECT 1  -- Assumed to have AT MOST one RC per OFFER in C1
                 FROM C1_OFFER_RC_TERM_MAP ortm, C1_OFFER_VALUES ofv2,        C1_RC_TERM_REF rtr
                WHERE ortm.offer_id = ofv.offer_id
                  AND ortm.offer_id = ofv2.offer_id
      AND ortm.rc_term_id = rtr.rc_term_id
                  AND nvl(rtr.APPLY_DAY,0)     = 0
                  AND ofv2.language_code=1
                  AND ofv2.display_value NOT IN ('DATA_SHARE_10',
                                                'DATA_SHARE_11',
                                                'DATA_SHARE_12',
                                                'DATA_SHARE_8',
                                                'DATA_SHARE_9',
                                                'EU_MIN_PACK_1',
                                                'EU_MIN_PACK_2',
                                                'ZERO_VP')
              )
    AND b.component_id  (+) = oi.member_id
    AND oi.service_order_id = TO_NUMBER(v_service_order_id)
  ORDER BY oi.is_cancelled, 
          b.component_id; ---- tymczasowe obejcie problemu

d_periodic_charge_row c_pc_to_add_list%ROWTYPE;

BEGIN

  OPEN c_pc_to_add_list;
  LOOP

    FETCH c_pc_to_add_list 
     INTO d_periodic_charge_row;
     EXIT WHEN c_pc_to_add_list%NOTFOUND;

    IF (d_count = 1) THEN
          -- d_periodic01 := d_periodic_charge_row.periodic_name;
          d_periodic01 := d_periodic_charge_row.display_value;

          SELECT nvl(rtr.APPLY_DAY,0), rtr.rc_term_id, d_periodic_charge_row.offer_id
           INTO d_apply_day, d_rc_term_id, d_offer_id
           -- NB:- This is dangerous because C1_OFFER_RC_TERM_MAP has pk on OFFER_ID, RC_TERM_ID, RESELLER_VERSION_ID
           -- and here we don't restrict on rc_term_id.
           -- This is because C1 solution is supposed to have AT MOST one RC per OFFER in C1
           -- 
           FROM C1_OFFER_RC_TERM_MAP ortm, C1_RC_TERM_REF rtr
          WHERE ortm.offer_id = d_periodic_charge_row.offer_id
            AND ortm.rc_term_id = rtr.rc_term_id
            -- AND nvl(rtr.APPLY_DAY,0)     = 0
            ;                          
    END IF;

    IF (d_count > 1) THEN /* we can support only connection of up to 1 pc in one service order/bundle limitation*/
      exit;
    END IF;

    d_count := d_count + 1;

  END LOOP;

  OPEN C1_OSO_PC_LIST_cv FOR
    SELECT d_periodic01 AS pc_name01, d_apply_day as pc_apply_day, d_rc_term_id      as pc_rc_term_id, d_offer_id as pc_offer_id
      FROM DUAL;

END;

Answer 1

您可以使用此Oracle exception来抓住此

EXCEPTION
WHEN NO_DATA_FOUND THEN
--do something here
END;

你可以在游标循环中放置一个BEGIN EXCEPTION END，这样即使没有找到一条记录的数据，循环仍会继续，或者只是在程序结束时使用它，在这种情况下循环将退出，处理将在第一个没有找到数据。

如何在sql中没有返回任何行时处理异常

1 个答案: