Question

如果一个是来自os.path.getatime()的str对象，你如何比较python中的2个日期我已将getatime()对象剥离到月，日和年，并将其转换为日期时间对象但我抛出一个值错误。

import os
from time import ctime, strftime
import datetime

folder = r'C:\users\c\desktop\files'
today = strftime("%Y-%m-%d")
present = datetime
files = os.listdir(folder)
for file in files:
    if file.endswith(".torrent"):
        # Get date time from each file then join file and folder to create full path
        date = ctime(os.path.getatime(os.path.join(folder, file)))
        # Remove the timestamp
        remove_timestamp = date.replace(date[11:19], "")
        # Remove the day
        new_date = remove_timestamp.replace(remove_timestamp[0:4], "")
        # print(new_date)
        if " " in new_date:
            # Replace space with a comma
            x = new_date.replace(" ", ",")
            if ",," in x:
                # Replace 2 commas with 1 coma
                z = x.replace(",,", ",")
                if "Mar" in z:
                    # Change month name to a number                        
                    mar = z.replace("Mar", "03")
                    # Problem start here
                    two_weeks = datetime.datetime(int(mar))
                    print(two_weeks)
                    # /Problem
                    if mar[4] is ",":
                        print(" " + mar, file)
                    else:
                        print(mar, file)
                if "Feb" in z:
                    # Change month name to a number
                    feb = z.replace("Feb", "02")
                    if feb[4] is ",":
                        print(" " + feb, file)
                    else:
                        print(feb, file)

错误

C:\Python34\python.exe C:/Users/c/PycharmProjects/untitled10/main.py
03,19,2015 some_file.torrent
Traceback (most recent call last):
  File "C:/Users/c/PycharmProjects/untitled10/main.py", line 30, in <module>
    two_weeks = datetime.datetime(int(mar))
ValueError: invalid literal for int() with base 10: '03,19,2015'

Process finished with exit code 1

Answer 1

os.path.getatime()返回＆＃34;秒以来＆＃34;秒作为浮点数（time.time()函数返回的值）。它是一个POSIX时间戳（＆＃34;自Epoch以来的秒数＆＃34; - 自1970-01-01 UTC以来经过的非飞跃SI秒数）在Python工作的常见系统上（除非＆＃34;右＆＃34 ;使用时区）。

要将其转换为表示UTC时间的日期时间对象，请调用datetime.utcfromtimestamp()方法。

不要混淆对象的字符串表示和对象本身。不要将时间/日期比作字符串，而是使用对象。

from datetime import datetime, timedelta

now = datetime.utcnow()
file_time = datetime.utcfromtimestamp(os.path.getmtime(filename))
if (now - file_time) > timedelta(1): 
    print("more than a day has passed")

请参阅Find if 24 hrs have passed between datetimes - Python。

Answer 2

当os.path.getatime返回一个时间戳时，使用带有（24％3600）的模数来粗略地获得一天精度的日期并不是更好。

如果您仍想将其转换为日期字符串，请比较您可以使用time.strptime(string[, format])的每个组件，它应该将字符串解析为日期组件的元组。

比较python中的文件访问日期

2 个答案: