使用mysql动态地将行转换为列

Question

我有如下表结构

+--------------------------------------+
ID | cmpgn_pic | cmpgn_dt   | cmpgn_tg |
+--------------------------------------+
|1 | NUSNAFIF  | 2015-04-01 | 300000   |
|2 | PETERBSG  | 2015-04-01 | 30000    |
|3 | PTYONG    | 2015-04-02 | 700000   |
|4 | HMKWAN    | 2015-04-01 | 800000   |
|5 | NUSNAFIF  | 2015-04-05 | 400000   |
|6 | NUSNAFIF  | 2015-04-02 | 100000   |
|7 | HMKWAN    | 2015-04-10 | 75000    |
|9 | PTYONG    | 2015-04-01 | 10000    |
|10| PTYONG    | 2015-04-05 | 600000   |
|11| NUSNAFIF  | 2015-04-05 | 600000   |
|12| HMKWAN    | 2015-04-10 | 800000   |
+--------------------------------------+

如何编写动态sql脚本以获得如下所示的结果

+---------------------------------------------------------------------------------------------------------------------------------------------+
| cmpgn_pic | 2015-04-01 | 2015-04-02 | 2015-04-03 | 2015-04-04 | 2015-04-05 | 2015-04-06 | 2015-04-07 | 2015-04-08 | 2015-04-09 | 2015-04-10 |
+---------------------------------------------------------------------------------------------------------------------------------------------+
| HMKWAN    | 1          | 0          | 0          | 0          | 0          | 0          | 0          | 0          | 0          | 2          |
| NUSNAFIF  | 1          | 1          | 0          | 0          | 2          | 0          | 0          | 0          | 0          | 0          |
| PETEGSG   | 1          | 0          | 0          | 0          | 0          | 0          | 0          | 0          | 0          | 0          |
| PTYONG    | 1          | 1          | 0          | 0          | 1          | 0          | 0          | 0          | 0          | 0          |

我只能编写如下的静态mysql脚本

SELECT cmpgn_pic, COUNT(id)
FROM t_prebook
group by 1

但我不知道如何在我的脚本中显示动态日期。我寻求你的帮助来解决我的问题。 提前谢谢你。

Answer 1

我认为问题已经回答了一段时间，请参考这个答案。

MySQL pivot row into dynamic number of columns

编辑：MySQL还没有PIVOT功能。您可能的解决方法是创建一个过程，将每个唯一的日期实例附加为新列。