Question

我尝试将小时数作为行数并将其按月拆分为列，以获得最终结果：

Hours                   Jan        Feb           Mar

08:00 To 08:59          1000     3500       2000

09:00 To 09:59         5000    6000       12000

ect ....................

我解决的字段是DateTime，其值为：

2014-01-01 08：02：34.000

我通过查询尝试：

SELECT   EntryDate, sum(LTOT) AS InvoiceTotal,

     sum(DATEPART(SECOND, EntryDate) + 60 * 
         DATEPART(MINUTE, EntryDate) + 3600 * 
         DATEPART(HOUR, EntryDate) 
        ) as 'TotalTime'

 FROM    AZTRH WHERE TR_TY = '102' AND

             LOC = '011' AND

             (CAST(AZTRH.EntryDate AS DATE) BETWEEN '2014-01-01' AND '2014-01-02') AND

             (CAST(AZTRH.EntryDate AS TIME) BETWEEN '08:00:00.000' AND '09:59:59.000') 

GROUP BY AZTRH.EntryDate, LTOT  

ORDER BY EntryDate

所以请问我怎么能得到我需要的结果？

Answer 1

尝试以下查询：

;WITH PivotSource
AS (
    SELECT  DATEPART(HOUR, t.EntryDate) AS EntryHour,
            MONTH(t.EntryDate) AS EntryMonth,
            t.LTOT
    FROM    ... 
    WHERE   ... 
)
SELECT  STR(p.EntryHour, 2, 0) + ':00 To' + STR(p.EntryHour, 2, 0)+':59'  AS [Hours],
        p.[1] AS Jan,
        p.[2] AS Feb,
        ...
FROM    PivotSource AS s
PIVOT( SUM(s.LTOT) FOR s.EntryMonth IN ([1], [2], [3], [4], [5], [6], [7], [8], [9], [10], [11], [12]) ) AS p

它使用：

DATEPART(HOUR, D/T value)从以提取小时部分，
MONTH(D/T value)到提取月份编号（1,2，...，12），
和PIVOT operator计算每小时和每月的SUM。

获得按小时分组的小时数作为行数和月数作为列数？

1 个答案: