Question

我的代码就像：

import java.util.Scanner;

public class CalcPyramidVolume {


public static void pyramidVolume (double baseLength, double baseWidth, double pyramidHeight) {
  double volume;
  volume = baseLength * baseWidth * pyramidHeight * 1/3;
  return;
}

public static void main (String [] args) {
  System.out.println("Volume for 1.0, 1.0, 1.0 is: " + pyramidVolume(1.0, 1.0, 1.0));
  return;
}
}

并且它说打印不能在void类型中完成。我只是不明白为什么......

Answer 1

void 方法不会返回主方法中可以附加到该String的任何内容。您需要使方法返回 double ，然后返回变量 volume ：

public static double pyramidVolume (double baseLength, double baseWidth, double pyramidHeight) {
  double volume;
  volume = baseLength * baseWidth * pyramidHeight * 1/3;
  return volume;
}

或更短：

public static double pyramidVolume (double baseLength, double baseWidth, double pyramidHeight) {
  return baseLength * baseWidth * pyramidHeight * 1/3;
}

另见：http://en.wikibooks.org/wiki/Java_Programming/Keywords/void

Answer 2

问题在于您使用的函数pyramidVolume基本上不返回任何内容。这应该有效：

import java.util.Scanner;

public class CalcPyramidVolume {


public static double pyramidVolume (double baseLength, double baseWidth, double pyramidHeight) {
  double volume;
  volume = baseLength * baseWidth * pyramidHeight * 1/3;
  return volume;
}

public static void main (String [] args) {
  System.out.println("Volume for 1.0, 1.0, 1.0 is: " + pyramidVolume(1.0, 1.0, 1.0).toString());
  return;
}
}

Answer 3

public class CalcPyramidVolume {
    public static double pyramidVolume (double baseLength, double baseWidth, double pyramidHeight) {
        double volume;
        volume = baseLength * baseWidth * pyramidHeight * 1/3;
        return volume;
    }

    public static void main (String [] args) {
        System.out.println("Volume for 1.0, 1.0, 1.0 is: " + CalcPyramidVolume.pyramidVolume(1.0, 1.0, 1.0));
    }
}

Java方法定义

3 个答案: