Question

我有一个表，我想选择一些行并按日期对它们进行分组。问题是when i'm selecting within my select that row appear to not grouped by date，请参阅示例：

SELECT date, SUM(price), (SELECT SUM(price), date FROM expense WHERE 
user = 'Catherine') as cprice FROM expense GROUP BY date

它没有对cprice进行分组，它会将所有凯瑟琳价格加起来并且不按日期对其进行分组，顺便说一下，我将GROUP BY日期考虑到内部选择但不起作用。任何建议？

expense table:
id   user      price   date
1    Frank      20     2014
2    Catherine  10     2013
3    Catherine  20     2014

谢谢

Answer 1

你可以试试这个：

SELECT 
  date, 
  SUM(price) as totalPrice, 
  SUM(IF(user='Catherine', price, 0)) as cprice 
FROM expense 
GROUP BY date

如果你想要两个价格在一起，那么你可以试试这个：

SELECT 
  date, 
  SUM(price) + SUM(IF(user='Catherine', price, 0)) as cprice
FROM expense 
GROUP BY date

Answer 2

尝试此查询，选择*行，其中user =＆＃39; Catherine＆＃39;并按日期对它们进行分组

SELECT 
     date,
     SUM(price)
FROM expense
WHERE user = 'Catherine'
GROUP BY date

Answer 3

尝试使用Case Statement :( 我不熟悉MySQL：（）

不确定，喜欢：

SELECT 
  date, 
  SUM(price) as totalPrice, 
  SUM(Case When user='Catherine' Then price Else 0 End CASE;) as catherine_price 
FROM expense 
GROUP BY date

Answer 4

你可能可以使用两个选择来解决它，并使用循环拉出你需要的数据。

在SELECT中选择GROUP BY

4 个答案: