在java中将字符串分解为句子（在指定组的符号出现之后）

Question

所以我写了下面的代码：

String text = "This is a string.        I want to break it into sentences";
String[] sentences = text.split("\\."); 

for (int i = 0; i < sentences.length; i++)
    System.out.println(sentences[i]);

此代码的输出为：

This is a string
        I want to break it into sentences

如何更改此代码以便

1. 每个新句子不仅会在＆＃34;。＆＃34;之后创建，也会在＆＃34;！＆＃34;之后创建。或＆＃34;？＆＃34;。
2. 句子开头不会有任何空格。

例如，如果我们有以下字符串

String text = "This is a string!   Is this a string?         I want to break it into sentences";

然后输出应该是：

This is a string
Is this a string
I want to break it into sentences

Answer 1

您可以使用字符类来分割点（.），?或!字符中的任何一个。要删除句子开头（可能还有结尾）的空格，您可以简单地修剪结果字符串：

String[] sentences = text.split("[.!?]");

for (int i = 0; i < sentences.length; i++) {
    System.out.println(sentences[i].trim());
}

Answer 2

将分隔符放在字符类中，并在char类旁边添加\\s*，这样它也会消耗以下零个或多个空格。

String[] sentences = text.split("[?!.]\\s*"); 

示例：

String text = "This is a string!   Is this a string?         I want to break it into sentences";
String[] parts = text.split("[?!.]\\s*"); 
for(String i: parts)
{
System.out.println(i);
}

<强>输出：

This is a string
Is this a string
I want to break it into sentences