var shots = Math.ceil(Math.random(0,1)*5);
var snd = new Audio("test.wav");
for (var i = 0; i < shots; i++){
snd.play();
}
现在,根据拍摄的“镜头”数量,我想播放test.wav相同的次数,其间有一个随机的,非常短的延迟,甚至可能“重叠”的声音效果相互影响
我最好怎么做呢? - 谢谢
答案 0 :(得分:0)
我会这样做...
var shots = Math.ceil(Math.random()*5), // Math.random() --> always 0-1 range
src = 'http://upload.wikimedia.org/wikipedia/en/f/f9/Beatles_eleanor_rigby.ogg', // change to your source
maxStartTime = 1000;
for(var i=0;i<shots;i++){
setTimeout(function(){
(new Audio(src)).play();
}, 100 + maxStartTime*(Math.random())); // again you can calibrate the timeout value to what suits you best
}