Question

这是我的输出

[{ "MFG_NAME": "ABC", "CONCATED_MKT_SHARE": "01-SEP-14|0.59" },
    { "MFG_NAME": "XYZ", "CONCATED_MKT_SHARE": "01-MAY-14|0.87" },
    { "MFG_NAME": "ABC", "CONCATED_MKT_SHARE": "01-NOV-14|0.25" },
    { "MFG_NAME": "XYZ", "CONCATED_MKT_SHARE": "01-JUL-14|0.67" },
    { "MFG_NAME": "ABC", "CONCATED_MKT_SHARE": "01-DEC-14|0.10" },
    { "MFG_NAME": "XYZ", "CONCATED_MKT_SHARE": "01-OCT-14|0.03" },
    { "MFG_NAME": "XYZ", "CONCATED_MKT_SHARE": "01-DEC-14|0.14" }]

在此ABC中，只有3个月SEP, NOV, DEC和XYZ的数据包含4个月MAY, JUL, OCT, DEC的数据。我试图从此输出中获取数据。但是由于这几个月我在实施它时遇到了问题。 ABC只有3个月，而其他9个月则缺失。同样在XYZ的情况下有4个月，而其他8个月则缺失。我试图用这个月替换这些缺失的月份，并将相应的值替换为0.0。

例如在ABC我尝试用01-OCT-14|0.0代替所有病例的月份之间缺少OCT。为此我写了下面的代码，但它不起作用。请更正代码。

var data = new Array();
data = ' [{ "MFG_NAME": "ABC", "CONCATED_MKT_SHARE": "01-SEP-14|0.59" },
    { "MFG_NAME": "XYZ", "CONCATED_MKT_SHARE": "01-MAY-14|0.87" },
    { "MFG_NAME": "ABC", "CONCATED_MKT_SHARE": "01-NOV-14|0.25" },
    { "MFG_NAME": "XYZ", "CONCATED_MKT_SHARE": "01-JUL-14|0.67" },
    { "MFG_NAME": "ABC", "CONCATED_MKT_SHARE": "01-DEC-14|0.10" },
    { "MFG_NAME": "XYZ", "CONCATED_MKT_SHARE": "01-OCT-14|0.03" },
    { "MFG_NAME": "XYZ", "CONCATED_MKT_SHARE": "01-DEC-14|0.14" }]';    

var currentTime = new Date();//Sat Mar 21 2015 17:19:15 GMT+0530
var monthNames = ["JAN","FEB","MAR","APR","MAY","JUN","JUL","AUG","SEP","OCT","NOV","DEC"];
var ctdate = (new Date()).getMonth() + 1; //Here I get the current month eg:MAR
var dynmonths = new Array();
dynmonths = monthNames.slice(ctdate).concat(monthNames.slice(0, ctdate));//Here I get previous 12 months for comparision 
//["APR","MAY","JUN","JUL","AUG","SEP","OCT","NOV","DEC","JAN","FEB","MAR"];
var MFG_NAME = [];
var DATE = [];
var MKT = [];

//替换月份的代码从这里开始

data.forEach(function(item) {
var share = item.CONCATED_MKT_SHARE;
for (var j = 0; j < dynmonths.length; j++) {
        if (share.indexOf('-' + dynmonths[j] + '-') == -1) {
            share += ',01-' + dynmonths[j] + '-14|0.0';
        }
    }// The months are replaced at the end, instead I want to replace it in order of the month names

//这是我的实际实现代码，我得到输出数组DATE和MKT

var share = item.CONCATED_MKT_SHARE;    
var parts = share.split("|");
var i = MFG_NAME.indexOf(item.MFG_NAME);
if (i == -1) {
    MFG_NAME.push(item.MFG_NAME);
    DATE.push([parts.shift()]);
    MKT.push([+parts.shift()]);
}
else {
    DATE[i].push(parts.shift());
    MKT[i].push(+parts.shift());
}

}）;

我正在接受DATE和MKT，但我没有得到失踪的月份

预期输出

 DATE[0] = ["01-APR-14","01-MAY-14","01-JUN-14","01-JUL-14","01-AUG-14","01-SEP-14","01-OCT-14","01-NOV-14","01-DEC-14","01-JAN-14","01-FEB-14","01-MAR-14"];

DATE[1] = ["01-APR-14","01-MAY-14","01-JUN-14","01-JUL-14","01-AUG-14","01-SEP-14","01-OCT-14","01-NOV-14","01-DEC-14","01-JAN-14","01-FEB-14","01-MAR-14"];

MKT[0] = ["0.0","0.0","0.0","0.0","0.0","0.59","0.0","0.25","0.10","0.0","0.0","0.0"];

MKT[1] = [""0.0","0.75","0.0","0.67","0.0","0.0","0.03","0.0","0.14"]

Answer 1

我已经创建了一个解决方案，你可以试试这个

var i=0;
for(var jo in pdata)
{
    DATE.push([]);
    MKT.push([]);
    for(var mnt in monthNames)
    {
        var index = pdata[jo].m.indexOf("01-"+monthNames[mnt]+"-14");
        if(index<0)
        {
            DATE[i].push("01-"+monthNames[mnt]+"-14");
            MKT[i].push("0.0");
        }
        else{
            DATE[i].push(pdata[jo].m[index]);
            MKT[i].push(pdata[jo].v[index]);
        }
    }
    i++;
}

var element = "";
for(i=0;i<DATE.length;i++)
{
    element += DATE[i].join(", ");
    element += "<br/>";
    element += MKT[i].join(", ");
    element += "<br/>";
}

请检查小提琴here

Answer 2

当@Learning发布他的答案时，我已经开始了，所以我刚刚完成了另一次拍摄。

http://jsfiddle.net/bvaughn/ah4c0oah/3/

var data = [
    { "MFG_NAME": "ABC", "CONCATED_MKT_SHARE": "01-SEP-14|0.59" },
    { "MFG_NAME": "XYZ", "CONCATED_MKT_SHARE": "01-MAY-14|0.87" },
    { "MFG_NAME": "ABC", "CONCATED_MKT_SHARE": "01-NOV-14|0.25" },
    { "MFG_NAME": "XYZ", "CONCATED_MKT_SHARE": "01-JUL-14|0.67" },
    { "MFG_NAME": "ABC", "CONCATED_MKT_SHARE": "01-DEC-14|0.10" },
    { "MFG_NAME": "XYZ", "CONCATED_MKT_SHARE": "01-OCT-14|0.03" },
    { "MFG_NAME": "XYZ", "CONCATED_MKT_SHARE": "01-DEC-14|0.14" }
];

var monthNames = ["JAN","FEB","MAR","APR","MAY","JUN","JUL","AUG","SEP","OCT","NOV","DEC"];

var DATES = [[], []];
var MARKETS = [[], []];

function findDataForMonth(mfgName, month) {
    for (var i = 0, length = data.length; i < length; i++) {
        var datum = data[i];

        if (datum.MFG_NAME === mfgName && datum.CONCATED_MKT_SHARE.indexOf(month) >= 0) {
            return datum.CONCATED_MKT_SHARE.split('|')[1];
        }
    }
}

var monthsToCheck = [];

function addMonthsForYear(year, minMonth, maxMonth) {
    for (var i = 0, length = monthNames.length; i < length; i++) {
        if ((!minMonth || i >= minMonth) && (!maxMonth || i <= maxMonth)) {
            monthsToCheck.push('01-' + monthNames[i] + '-' + year);
        }
    }
}

var monthOffset = new Date().getMonth();

addMonthsForYear(12, monthOffset);
addMonthsForYear(13);
addMonthsForYear(14);
addMonthsForYear(15, undefined, monthOffset);

for (var i = 0, length = monthsToCheck.length; i < length; i++) {
    var month = monthsToCheck[i];

    MARKETS[0].push(findDataForMonth("ABC", month) || 0.0);
    MARKETS[1].push(findDataForMonth("XYZ", month) || 0.0);

    DATES[0].push(month);
    DATES[1].push(month);
}

console.log(DATES);
console.log(MARKETS);

使用jquery替换丢失的月份

2 个答案: