Question

我从数据库中获取客户端名称列表，我需要将该列表填充到Play框架中的下拉列表中。当我这样做时，我收到一个错误：not found type name。我做错了什么？

我的Application.java代码是：

package controllers;
import java.awt.List;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Statement;



import play.mvc.*;
import play.twirl.api.Content;
public class Application extends Controller {

    static List l = new List();

    public static <list> Result index() throws InstantiationException, IllegalAccessException, ClassNotFoundException, SQLException{
        Class.forName("com.microsoft.sqlserver.jdbc.SQLServerDriver").newInstance();
        Connection conn = DriverManager.getConnection("jdbc:sqlserver://localhost:1433","SUMEET","sumeet");
        System.out.println(conn);
        Statement sta = conn.createStatement();
        String Sql = "select * from client";
        ResultSet rs = sta.executeQuery(Sql);
        while (((ResultSet) rs).next()) {
         String ID= rs.getString("ClientName");
            l.add(ID);
        }
        return ok((Content) l);



      }

}

`

和我的index.scala.html文件是

    @import helper._
@main {


            @select(
                options(@message), 
                '_label -> "Company", '_default -> "-- Choose a company --",
                '_showConstraints -> false
            )


}

Answer 1

  @(ConsultantList:java.util.List[String])
@import helper._
@main("ADAMS") {
---------
---------
@for(element <- ConsultantList){
                <option value="@element">@element</option>
          }

在Play框架中填充下拉列表

1 个答案: