Question

我开始构建一个非常简单的产品展示系统，主要是为了建立我自己的技能，但也可以在我的网站上使用。

list.php的

<html>
<head>
<title>Retrieve data from the database</title>
<?php
$username='';
$password='';
$database='';
?>
</head>
<body>

<ul>

<?php
// Connect to database server
mysql_connect(localhost,$username,$password); 


// Select database
@mysql_select_db($database) or die( 'Unable to select database');  

// SQL query
$sql = "SELECT * FROM products WHERE category = 30";

// Execute the query (the recordset $rs contains the result)
$result = mysql_query($sql);

// Loop the recordset $rs
while($row = mysql_fetch_array($result)) {

   // Name of the person
  $strName = $row['make'];  
       // Create a link to person.php with the id-value in the URL
   $strLink = "<a href = 'product.php?id = " . $row['ID'] . "'>" . $strName . "</a>";

    // List link
   echo "<li>" . $strLink . "</li>";

  }

// Close the database connection
mysql_close();
?>

</ul>
</body>
</html>

Product.php

<html>
<head>
<title>Retrieve data from database</title>
</head>
<body>

<?php

$username="";
$password="";
$database="";
// Connect to database server
mysql_connect(localhost,$username,$password); 


// Select database
@mysql_select_db($database) or die( "Unable to select database");
// Get data from the database depending on the value of the id in the URL
$sql = mysql_query('SELECT * FROM products WHERE ID=' . $_GET["ID"]);

$result = mysql_query($sql); 

if(!$result)
    die(mysql_error());

// Loop the recordset 
while($row = mysql_fetch_array($result)) {

    // Write the data of the product
    echo $row['category'];
    echo "<p>";
    echo $row["make"];
    echo "<p>";
    echo $row["description"];
    echo "<p>";
    echo $row["picture"];
}

// Close the database connection
mysql_close();
?>

<p><a href="list.php">Return to the list</a></p>

</body>

</html>

可以看到弄乱HERE

如果有人可以帮我解决这个问题，我将非常感激！

Answer 1

尝试这种方式，但不完全确定这个顽固的问题。您可以尝试使用$_GET

将array_change_key_case()数组的所有键的大小写更改为小写

$get = array_change_key_case($_GET);
$id = $get['id'];

$sql = mysql_query('SELECT * FROM products WHERE ID=' . $id);

NB：首先确定SELECT * FROM products WHERE ID=your_row_id是否返回结果？

Answer 2

我发现页面'list.php'生成的链接格式不正确。

改变了这个：

$strLink = "<a href = 'product.php?id = " . $row['ID'] . "'>" . $strName . "</a>";

到

$strLink = "<a href = 'product.php?id=".$row['ID']."'>" . $strName . "</a>";

它现在正如它应该的那样工作！

查询是空的错误，我无法解决原因

2 个答案: