我想在2010年5月16日（星期日）和5月25日（星期二）之间输出所有工作日（MON-FRI）。正确的输出应为17,18,19,20,21,24,25。但是，得到的结果是17,18,19,20,21,17,18,19。其他方法只是将日期所在的字符串拆分为
import java.util.*;
public class test
{
public static void main(String[] args) {
String startTime = "5/16/2010 11:44 AM";
String endTime = "5/25/2010 12:00 PM";
GregorianCalendar startCal = new GregorianCalendar();
startCal.setLenient(true);
String[] start = splitString(startTime);
//this sets year, month day
startCal.set(Integer.parseInt(start[2]),Integer.parseInt(start[0])-1,Integer.parseInt(start[1]));
startCal.set(GregorianCalendar.HOUR, Integer.parseInt(start[3]));
startCal.set(GregorianCalendar.MINUTE, Integer.parseInt(start[4]));
if (start[5].equalsIgnoreCase("AM")) { startCal.set(GregorianCalendar.AM_PM, 0); }
else { startCal.set(GregorianCalendar.AM_PM, 1); }
GregorianCalendar endCal = new GregorianCalendar();
endCal.setLenient(true);
String[] end = splitString(endTime);
endCal.set(Integer.parseInt(end[2]),Integer.parseInt(end[0])-1,Integer.parseInt(end[1]));
endCal.set(GregorianCalendar.HOUR, Integer.parseInt(end[3]));
endCal.set(GregorianCalendar.MINUTE, Integer.parseInt(end[4]));
if (end[5].equalsIgnoreCase("AM")) { endCal.set(GregorianCalendar.AM_PM, 0); }
else { endCal.set(GregorianCalendar.AM_PM, 1); }
for (int i = startCal.get(Calendar.DATE); i < endCal.get(Calendar.DATE); i++)
{
startCal.set(Calendar.DATE, i);
startCal.set(Calendar.DAY_OF_WEEK, i);
if (startCal.get(Calendar.DAY_OF_WEEK) == Calendar.MONDAY || startCal.get(Calendar.DAY_OF_WEEK) == Calendar.TUESDAY || startCal.get(Calendar.DAY_OF_WEEK) == Calendar.WEDNESDAY || startCal.get(Calendar.DAY_OF_WEEK) == Calendar.THURSDAY || startCal.get(Calendar.DAY_OF_WEEK) == Calendar.FRIDAY)
{
System.out.println("\t" + startCal.get(Calendar.DATE));
}
}
}
private static String[] splitDate(String date)
{
String[] temp1 = date.split(" "); // split by space
String[] temp2 = temp1[0].split("/"); // split by /
//5/21/2010 10:00 AM
return temp2; // return 5 21 2010 in one array
}
private static String[] splitTime(String date)
{
String[] temp1 = date.split(" "); // split by space
String[] temp2 = temp1[1].split(":"); // split by :
//5/21/2010 10:00 AM
String[] temp3 = {temp2[0], temp2[1], temp1[2]};
return temp3; // return 10 00 AM in one array
}
private static String[] splitString(String date)
{
String[] temp1 = splitDate(date);
String[] temp2 = splitTime(date);
String[] temp3 = new String[6];
return dateFill(temp3, temp2[0], temp2[1], temp2[2], temp1[0], temp1[1], temp1[2]);
}
private static String[] dateFill(String[] date, String hours, String minutes, String ampm, String month, String day, String year) {
date[0] = month;
date[1] = day;
date[2] = year;
date[3] = hours;
date[4] = minutes;
date[5] = ampm;
return date;
}
private String dateString(String[] date) {
//return month+" "+day+", "+year+" "+hours+":"+minutes+" "+ampm
//5/21/2010 10:00 AM
return date[3]+"/"+date[4]+"/ "+date[5]+" "+date[0]+":"+date[1]+" "+date[2];
}
}
答案 0 :(得分：1)
这段代码不好。
我不明白你为什么要对字符串进行所有这些解析来获取Date，反之亦然，当你有java.text.DateFormat和java.text.SimpleDateFormat为你轻松完成时。
我认为这更好。看看你是否同意：
package com.contacts.util;
import java.text.DateFormat;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.ArrayList;
import java.util.Calendar;
import java.util.Date;
import java.util.List;
public class DateUtils
{
private static final DateFormat DEFAULT_FORMAT = new SimpleDateFormat("dd-MMM-yyyy");
public static void main(String[] args)
{
try
{
Date startDate = ((args.length > 0) ? DEFAULT_FORMAT.parse(args[0]) : new Date());
Date endDate = ((args.length > 1) ? DEFAULT_FORMAT.parse(args[1]) : new Date());
List<Date> weekdays = DateUtils.getWeekdays(startDate, endDate);
Calendar calendar = Calendar.getInstance();
for (Date d : weekdays)
{
calendar.setTime(d);
int dayOfMonth = calendar.get(Calendar.DAY_OF_MONTH);
int month = calendar.get(Calendar.MONTH);
int year = calendar.get(Calendar.YEAR);
// System.out.println(DEFAULT_FORMAT.format(d));
System.out.println("day: " + dayOfMonth + " month: " + (month+1) + " year: " + year);
}
}
catch (ParseException e)
{
e.printStackTrace();
}
}
public static List<Date> getWeekdays(Date startDate, Date endDate)
{
List<Date> weekdays = new ArrayList<Date>();
if ((startDate == null) || (endDate == null))
return weekdays;
if (startDate.equals(endDate))
{
if (isWeekday(startDate))
{
weekdays.add(startDate);
}
}
else if (startDate.after(endDate))
{
weekdays = getWeekdays(endDate, startDate);
}
else
{
Calendar calendar = Calendar.getInstance();
calendar.setTime(startDate);
Date d = startDate;
while (endDate.equals(d) || endDate.after(d))
{
if (isWeekday(d))
{
weekdays.add(d);
}
calendar.add(Calendar.DATE, 1);
d = calendar.getTime();
}
}
return weekdays;
}
public static boolean isWeekday(Date d)
{
if (d == null)
return false;
Calendar calendar = Calendar.getInstance();
calendar.setTime(d);
int dayOfWeek = calendar.get(Calendar.DAY_OF_WEEK);
return ((dayOfWeek >= Calendar.MONDAY) && (dayOfWeek <= Calendar.FRIDAY));
}
}
答案 1 :(得分：1)
startCal.set(Calendar.DAY_OF_WEEK, i);每7个循环将翻转你的日期。
答案 2 :(得分：0)
我不知道这是否是您的代码的问题，但JDK对Calendar常量使用了一些意外的值。例如，月份为零。换句话说，Calendar.JANUARY为0.另一方面，工作日为1到7，从星期日开始为1.等等。
答案 3 :(得分：0)
我很幸运地对Java中的Date知之甚少，但我知道它基本上是一个困难和糟糕的API。去JodaTime，直到新的JSR-310完成。