Question

我在Google表单中使用表单通知加载项。我编辑了Code.gs和CreatorNotification.html文件，一切正常 - 当提交Google表单时，我收到了一封电子邮件。现在，我正在尝试将表单提交中的一些字段添加到电子邮件中。但是根据我在下面添加的修改，电子邮件通知将停止工作。

在Code.gs脚本中，我有：

function sendCreatorNotification() {
    var form = FormApp.getActiveForm();
    var settings = PropertiesService.getDocumentProperties();
    var responseStep = settings.getProperty('responseStep');
    responseStep = responseStep ? parseInt(responseStep) : 10;

    function onFormSubmit(e) {
        //Get information from form and set as variables
        var First_Name = e.value[2];

        // If the total number of form responses is an even multiple of the
        // response step setting, send a notification email(s) to the form
        // creator(s). For example, if the response step is 10, notifications
        // will be sent when there are 10, 20, 30, etc. total form responses
        // received.
        if (form.getResponses().length % responseStep == 0) {
            var addresses = settings.getProperty('creatorEmail').split(',');
            if (MailApp.getRemainingDailyQuota() > addresses.length) {
                var template = HtmlService.createTemplateFromFile('CreatorNotification');
                template.summary = form.getSummaryUrl();
                template.responses = form.getResponses().length;
                template.title = form.getTitle();
                template.responseStep = responseStep;
                template.formUrl = form.getEditUrl();
                template.notice = NOTICE;
                template.firstname = First_Name;
                var message = template.evaluate();
                MailApp.sendEmail(settings.getProperty('creatorEmail'),
                form.getTitle() + ': Case submission',
                message.getContent(), {
                    name: ADDON_TITLE,
                    htmlBody: message.getContent()
                });
            }
        }
    }
}

在CreatorNotification.html中，我有：

<p><i>Form Notifications</i> (a Google Forms add-on) has detected that the      form
titled <a href="<?= formUrl?>"><b><?= title ?></b></a> has received
<?= responses ?> responses so far.</p>

<p><a href="<?= summary ?>">Summary of form responses</a></p>

<p>First Name:</p> <?= firstname ?>

任何方向都会受到赞赏。

Answer 1

您正在尝试运行两个触发器。 “附加”代码创建了一个触发器。加载项创建“可安装”触发器。您已为要提交的表单设置了一个触发器。 onFormSubmit(e)函数是一个“简单”触发器。因此，您在设置表单时设置了两个触发器。所以，你创造了一个冲突。如果查看“资源”菜单，在“CURRENT PROJECT”的TRIGGERS下，您应该会看到为sendCreatorNotification()函数定义的触发器。

这是你可以尝试的。您不需要单独的onFormSubmit(e)简单触发器。 sendCreatorNotification()函数具有可用的事件对象。只需将e添加到sendCreatorNotification()函数：

sendCreatorNotification(e)

编写代码以从e中获取值。

通知电子邮件中的Google表单回复

1 个答案: