逐字段比较两个CSV文件并列出所有不匹配项

时间:2015-03-20 13:35:08

标签: python python-2.7 csv python-3.x compare

我尝试使用Python代码比较两个CSV文件。但我的代码并没有显示所有的不匹配。它只会显示每行的第一个不匹配。我需要特定行中的所有不匹配。

Python代码:

import csv, itertools
column_names = ['id','name','amount']
source_data = csv.reader(open('src.csv'))
target_data = csv.reader(open('tgt.csv'))
counter = 1
def rowElementCompare(sourceRow, targetRow):
    row_length = min(len(sourceRow), len(targetRow))
    for i in range(row_length):
        if sourceRow[i] != targetRow[i]:
            print i
            return i        
    return None
for source_row,target_row in itertools.izip(source_data,target_data):
    comparison_result = None
    comparison_result = rowElementCompare(source_row, target_row)
    #print (comparison_result)
    if comparison_result != None: #comparison_result is the column index at which the mismatch occured
        print "Mismatch in column %s on row number %d , source value %s, target value %s" % (column_names[comparison_result], counter, source_row[comparison_result], target_row[comparison_result])
    counter += 1

文件1:

id,name,amount
1,bob,20
3,eva,8
3,sarah,7
4,jeff,19
6,fred,10

文件2:

id,name,amount
1,bob,23
3,sarah,7
4,jeff,19
5,mira,81
6,fred,13

输出我的代码:

Mismatch in column amount on row number 2 , source value 20, target value 23 
Mismatch in column name on row number 3 , source value eva, target value sarah 
Mismatch in column id on row number 4 , source value 3, target value 4 
Mismatch in column id on row number 5 , source value 4, target value 5      
Mismatch in column amount on row number 6 , source value 10, target value 13

预期产出:

Mismatch in column amount on row number 2 , source value 20, target value 23 
Mismatch in column name on row number 3 , source value eva, target value sarah 
Mismatch in column id on row number 4 , source value 3, target value 4 
Mismatch in column name on row number 4 , source value sarah, target value jeff 
Mismatch in column age on row number 4 , source value 7, target value 19 
Mismatch in column id on row number 5 , source value 4, target value 5 
Mismatch in column name on row number 5 , source value jeff, target value mira 
Mismatch in column age on row number 5 , source value 19, target value 81 
...

1 个答案:

答案 0 :(得分:1)

问题是你每行只调用rowElementCompare一次。此外,重复调用它将无济于事,因为它总是从行的开头开始,一旦找到第一个不匹配就停止。

解决此问题的一种方法是将rowElementCompare更改为yield其结果,而不是将其返回。这样你就可以遍历那一行中的所有不匹配。

这是更新的代码。更改的行标有# UPDATED

import csv, itertools
column_names = ['id','name','amount']
source_data = csv.reader(open('foo1.csv'))
target_data = csv.reader(open('foo2.csv'))
counter = 1
def rowElementCompare(sourceRow, targetRow):
    row_length = min(len(sourceRow), len(targetRow))
    for i in range(row_length):
        if sourceRow[i] != targetRow[i]:
            print i
            yield i # UPDATED
    return # UPDATED
for source_row,target_row in itertools.izip(source_data,target_data):
    comparison_result = None
    for comparison_result in rowElementCompare(source_row, target_row): # UPDATED
        print "Mismatch in column %s on row number %d , source value %s, target value %s" % (column_names[comparison_result], counter, source_row[comparison_result], target_row[comparison_result])
    counter += 1

清理代码的另一个小建议:你可以使用枚举来避免手动更新计数器变量。

for counter,(source_row,target_row) in enumerate(itertools.izip(source_data,target_data), start=1):